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nata0808 [166]
4 years ago
10

Using the kinetic theory what happens to oxygen particles as they are cooled

Chemistry
2 answers:
Irina18 [472]4 years ago
6 0

If it is cooled the motion of the particles decreases as they lose energy.

Fofino [41]4 years ago
3 0

The motion of the particles decrease as they lose energy.

Hopefully this answered your question.

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An emulsifying agent is typically characterized by having
pochemuha

The third substance or agent which produce the film between the interface of two immiscible liquids and thus stabilize the system are known as an emulsifying agent.

Since the solubility of the liquids depends on the polarity of the mixing liquids the thumb rule of solubility is like dissolves like that means polar liquid dissolves in polar liquid only and vice versa. For two immiscible liquids, the emulsifying agent is used which does not chemically change the polarity of liquids but acts as bridge between immiscible liquids, the polar end of the emulsifier attach to the polar liquid and the non-polar end of the emulsifier attach to the non-polar end and thus help in dissolving.

Therefore, the one end of the emulsifier is polar and the other end is non-polar

5 0
4 years ago
A new penny has a mass of 2.49 grams and occupies 0.349 cm cubed. If pure copper has a density of 8.96 g/cm cubed, is the new pe
lys-0071 [83]

Answer: The new penny is not pure copper

Explanation:

Density \rho is defined as a relation between the mass m and the volume V:

\rho=\frac{m}{V}

Now, we are told the density of pure copper is:

\rho_{copper}=8.96 g/cm^{3}

And we are given the mass and volume of the new penny, with which we can calculate its density:

\rho_{penny}=\frac{m_{penny}}{V_{penny}}=\frac{2.49 g}{0.349 cm^{3}}

\rho_{penny}=7.13 g/cm^{3} As we can see the density of this penny is not equal to the density of pure copper, hence the new penny is not pure copper.

8 0
4 years ago
8.03 Solutions Lab Report<br> Does anyone have a PDF or Document of FLVS 8.03 Solutions Lab
GarryVolchara [31]

8.03 solutions report is described below.

Explanation:

8.03 Solutions Lab Report

In this laboratory activity, you will investigate how temperature, agitation, particle size, and dilution affect the taste of a drink. Fill in each section of this lab report and submit it and your pre-lab answers to your instructor for grading.  

Pre-lab Questions:

In this lab, you will make fruit drinks with powdered drink mix. Complete the pre-lab questions to get the values you need for your drink solutions.  

Calculate the molar mass of powered fruit drink mix, made from sucrose (C12H22O11).

Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL.

7 0
4 years ago
Read 2 more answers
Physical changes in water are most often caused by
marusya05 [52]

the answer would be B. temperature

7 0
3 years ago
A bike tire has a volume of 0.850L at a pressure of 40.0 psi and 0.00°C. What will be the
Tema [17]

Answer:

45.13 psi

Explanation:

Assuming the volume does not change

P1/T1 = P2/T2         T  must be in Kelvin

40/(273.15) = P2/(273.15 + 35)       P2 = 45.13 psi

4 0
2 years ago
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