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nata0808 [166]
3 years ago
10

Using the kinetic theory what happens to oxygen particles as they are cooled

Chemistry
2 answers:
Irina18 [472]3 years ago
6 0

If it is cooled the motion of the particles decreases as they lose energy.

Fofino [41]3 years ago
3 0

The motion of the particles decrease as they lose energy.

Hopefully this answered your question.

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Abu Ali al-Hasa invented the words____and___
xz_007 [3.2K]
Huh I don’t know this
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3 0
2 years ago
How would a sandblasted rock differ from a rock that hasn't been sandblasted?
steposvetlana [31]
A non-sandblasted rock could be rough or smooth depending on how it was formed.

A sandblasted rock should be much smoother, since the sand blasts away any rough edges. It will, however, be slightly smaller due to losing those edges.
3 0
2 years ago
_Al(NO3)3 +_(NH4)3 P04_AlPO4+_ NH, NO3<br>balancing equations​
astra-53 [7]

Answer:

Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + 3NH₄NO₃

The coefficients are: 1, 1, 1, 3

Explanation:

__Al(NO₃)₃ + __(NH₄)₃PO₄ —> __AlPO₄ + __NH₄NO₃

The above equation can be balance as illustrated below:

Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + NH₄NO₃

There are 12 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 3 before NH₄NO₃ as shown below:

Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + 3NH₄NO₃

Now the equation is balanced.

The coefficients are: 1, 1, 1, 3

4 0
2 years ago
You produce 500 ml of a 0.001 m hclo4, which ionizes completely in water. What is the ph you should expect?
Alina [70]

Answer:

pH+3.0 normality

Explanation:

8 0
1 year ago
¿Cuál es el % m/m de una disolución en que hay disueltos 22 g de soluto en 44 g de disolvente?
Archy [21]

The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?

Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

Explanation:

Given: Mass of solute = 22 g

Mass of solvent = 44 g

The percentage m/m is calculated using the following formula.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100

Substitute the values into above formula as follows.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{22 g}{44 g} \times 100\\= 50 percent

Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

5 0
2 years ago
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