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3 years ago

Using the kinetic theory what happens to oxygen particles as they are cooled

Chemistry

2 answers:

Irina18 [472]3 years ago

6 0

If it is cooled the motion of the particles decreases as they lose energy.

Fofino [41]3 years ago

3 0

The motion of the particles decrease as they lose energy.

Hopefully this answered your question.

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Pyruvic acid can be regarded as the end product of _________________.

Alex_Xolod [135]

Pyruvic acid is the end product of the Link reaction in respiration.

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3 0

3 years ago

Define, giving examples of Binary ionic Compound:

Gnesinka [82]

Answer:

A binary ionic compound contains an ion that is a metal (cation) and an ion that is a nonmetal (anion).

Explanation:

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8 0

2 years ago

A container holds 40.0 mL of nitrogen at 30° C and at a constant pressure.

Leokris [45]

Answer:

The correct answer is - 46.60 mL.

Explanation:

To find the volume of the gas at its new increased temperature we need to use Charl Law that shows the direct relationship between Volume and Temperature while Pressure remains constant.

V1 = 40 ml

T1 = 30 degree C + 273 = 303 K

V2 = ?

T2 = 80 degree C + 273 = 353 K

Charl Equation is:

V 1/T 1 = V 2/ T 2

(V1) * (T2)/ T1= V2

placing value:

40*353/303 = V2

= 14120/303

Vf = 46.60 mL

3 0

2 years ago

At what temperature does oxygen turn from a solid into a liquid (in °C)?

horrorfan [7]

Answer:

‑297 degrees Fahrenheit (‑183 degrees Celsius).

Explanation:

6 0

3 years ago

Read 2 more answers

A 4.0 L flask containing N2 at 15 atm is connected to a 4.0 L flask containing H2 at 7.0 atm and the gases are allowed to mix. W

LekaFEV [45]

The mole fraction of N₂ after the mixture of 4.0 L of N₂ at 15 atm with 4.0 L of H₂ at 7.0 atm is 0.68.

We can calculate the mole fraction of N₂ with the following equation:

$X_{N_{2}} = \frac{n_{N_{2}}}{n_{t}} = \frac{n_{N_{2}}}{n_{N_{2}} + n_{H_{2}}}$ (1)

The number of moles of N₂ and H₂ can be found with the ideal gas law:

$PV = nRT$

Where:

P: is the pressure

R: is the gas constant

T: is the temperature

V: is the volume

For nitrogen gas we have:

$n_{N_{2}} = \frac{P_{N_{2}}V_{N_{2}}}{RT}$ (2)

And for hydrogen:

$n_{H_{2}} = \frac{P_{H_{2}}V_{H_{2}}}{RT}$ (3)

After entering equations (2) and (3) into (1), we get:

$X_{N_{2}} = \frac{\frac{P_{N_{2}}V_{N_{2}}}{RT}}{\frac{P_{N_{2}}V_{N_{2}}}{RT} + \frac{P_{H_{2}}V_{H_{2}}}{RT}}$

Since RT are constants, we have:

$X_{N_{2}} = \frac{P_{N_{2}}V_{N_{2}}}{P_{N_{2}}V_{N_{2}} + P_{H_{2}}V_{H_{2}}}$

We know that:

$P_{N_{2}} = 15 atm$

$V_{N_{2}} = 4.0 L$

$P_{H_{2}} = 7.0 atm$

$V_{H_{2}} = 4.0 L$

so:

$X_{N_{2}} = \frac{15 atm*4.0 L}{15 atm*4.0 L + 7.0 amt*4.0 L} = 0.68$

Therefore, the mole fraction of N₂ is 0.68.

Find more here:

brainly.com/question/4147359?referrer=searchResults

I hope it helps you!

6 0

2 years ago