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vekshin1
3 years ago
14

4. Both the alkene C4H8 and the alkyne C4H6 have rigid bond structures. However, C4H8 can form three isomers, whereas C4H6 can f

orm only two isomers. Why is this so?
Chemistry
1 answer:
Murrr4er [49]3 years ago
3 0
Both alkene C4H8 and alkyne C4H6 have rigid bond structures. C4H8 can form three isomers while C4H6 can only form two isomers. Isomers are defined as two or more compounds having the same formula but with different molecular arrangements. The alkene contains 1 double bond which connects 2 carbons, so the other 4 hydrogen atoms can be rearranged. The alkyne only has 2 extra hydrogen atoms. 
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An unknown gas is contained in a sealed container. Over time, the gas is gradually cooled until it becomes a solid. Determine wh
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Answer:D molecular attraction increases as temp decreases

Explanation:A,B would require data not available. C is missing. The question is a mess.

5 0
3 years ago
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A student has a 2.19 L bottle that contains a mixture of O 2 , N 2 , and CO 2 with a total pressure of 5.57 bar at 298 K . She k
Sergeeva-Olga [200]

<u>Answer:</u> The partial pressure of oxygen gas is 2.76 bar

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 5.57 bar

V = Volume of the gas = 2.19 L

T = Temperature of the gas = 298 K

R = Gas constant = 0.0831\text{ L bar }mol^{-1}K^{-1}

n = Total number of moles = ?

Putting values in above equation, we get:

5.57bar\times 2.19L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{5.57\times 2.19}{0.0831\times 298}=0.493mol

To calculate the mole fraction of carbon dioxide, we use the equation given by Raoult's law, which is:

p_{A}=p_T\times \chi_{A}         ........(1)

where,

p_A = partial pressure of carbon dioxide = 0.318 bar

p_T = total pressure = 5.57 bar

\chi_A = mole fraction of carbon dioxide = ?

Putting values in above equation, we get:

0.318bar=5.57bar\times \chi_{CO_2}\\\\\chi_{CO_2}=\frac{0.381}{5.57}=0.0571

  • Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

We are given:

Moles of nitrogen gas = 0.221 moles

Mole fraction of nitrogen gas, \chi_{N_2}=\frac{0.221}{0.493}=0.448

Calculating the partial pressure of oxygen gas by using equation 1, we get:

Mole fraction of oxygen gas = (1 - 0.0571 - 0.448) = 0.4949

Total pressure of the system = 5.57 bar

Putting values in equation 1, we get:

p_{O_2}=5.57bar\times 0.4949\\\\p_{O_2}=2.76bar

Hence, the partial pressure of oxygen gas is 2.76 bar

6 0
3 years ago
A student performs an exothermic reaction in a beaker and measures the temperature. If the thermometer initially reads 35 degree
Ksju [112]

Answer:

C

Explanation:

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7 0
2 years ago
How much energy is required to raise the temperature of 3 kg of iron from 20° C to 25°C? Use the table below and this equation:
ElenaW [278]

The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)

<u>Explanation:</u>

Given:

Specific Heat capacity of Iron= 0.450 J/ g °C

To Find:

Required Energy to raise the Temperature

Formula:

Amount of energy required is given by the formula,

Q = mC (ΔT)

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Plugin the values, we will get,

Q = 3000 g ×  0.450 J/ g °C ×  5°C

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7 0
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gavmur [86]
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Equation  is  as follows

 CH3 CH(CH3) CH2  C=C CH2 CH(CH3)  CH3  +  H2
→

CH3 CH(CH3)CH2 CH2 CH2 CH2 CH(CH3) CH3

metal catalyst  example is nickel  and the name  of structure formed is 
2,7-  dimethyl octane
6 0
3 years ago
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