Answer:
P2O3
Explanation:
Firstly, we know that the phosphorus would absorb oxygen from air to form its oxide. We already know the mass of the phosphorus, we can get the mass of the oxygen by subtracting the mass of the phosphorus from the mass of the oxide.
The mass of the oxygen is 2.57 - 1.45 = 1.12g
From here, we covert these masses to moles by dividing by the atomic masses of phosphorus and oxygen respectively.
The atomic mass of phosphorus is 31 while that of oxygen is 16.
P = 1.45/31 = 0.046774193548
O = 1.12/16 = 0.07
We now divide by the smallest which is that of phosphorus.
P = 0.046774193548/ 0.046774193548= 1
O = 0.07/ 0.046774193548 = 1.5
We then multiply the answers by 2 for conversion to whole numbers. Making P = 2 and O = 3
The empirical formula is thus P2O3
Nonmetals don’t have enough electronegativity to transfer electrons so the electrons are shared between them
Explanation:
We have to find the number of moles of N₂ that are present in a sample that has a volume of 40.0 L at STP.
STP means Standard Conditions of Temperature and Pressure. These conditions are 273.15 K and 1 atm. We know that 1 mol of N₂ will occupy 22.4 L. We can use that ratio to find the answer to our problem.
1 mol of N₂ = 22.4 L
moles of N₂ = 40.0 L * 1 mol/(22.4 L)
moles of N₂ = 1.79 mol
Answer: 1.79 moles of nitrogen are present.
The answer is basic solution
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