I thinks it’s 2...........
All stars in a stellar cluster have roughly the same distance.
<h3>What coloration are celebrity clusters?</h3>
Open clusters have a tendency to be blue in color. They frequently include glowing gas and dust. The stars in an open cluster are young stars that all formed from the equal nebula. These warm blue stars are in an open cluster known as the Jewel Bo
<h3>Are stars in the identical cluster?</h3>
Though stellar associations are grouped in with megastar clusters, they're pretty a bit different. "Stellar associations are companies of tens to hundreds of stars that have similar a while and metallicities, and are moving in roughly the equal direction within the galaxy, but are no longer gravitationally bound," Geller said.
Learn more about star cluster here:
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brainly.com/question/20326847</h3><h3 /><h3>#SPJ4</h3>
The formula used to find potential energy is <em>P.E. = M * G * H</em> (P.E. is potential energy, M is mass, G is gravitational pull, and H is height). So the answer to your question is <em>5 * 9.8 * 2</em>, which equals 98.
Competition in the Los Angeles Flower District results in better quality flowers.
<h3>Why quality is the standard in flower competition?</h3>
Competition results in better quality flowers because in the competition, best quality of flowers will be selected as a winner so the competitors produces best quality of flowers in order to claim the prize so we can conclude that Competition in the Los Angeles Flower District results in better quality flowers
Learn more about competition here: brainly.com/question/25605883
Answer:
A u = 0.36c B u = 0.961c
Explanation:
In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains
u ’= (u-v) / (1- uv / c²)
Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory
The data give is u ’= 0.43c and the initial core velocity v = 0.94c
Let's clear the speed with respect to the observer (u)
u’ (1- u v / c²) = u -v
u + u ’uv / c² = v - u’
u (1 + u ’v / c²) = v - u’
u = (v-u ’) / (1+ u’ v / c²)
Let's calculate
u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)
u = 0.51c / (1 + 0.4042)
u = 0.36c
We repeat the calculation for the other piece
In this case u ’= - 0.35c
We calculate
u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)
u = 1.29c / (1- 0.329)
u = 0.961c
