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3 years ago

What type of acceleration does an object moving in a circular path with constant speed experience?

Physics

2 answers:

Marysya12 [62]3 years ago

7 0

An object moving in a circular path has centripetal acceleration. <em>(A)</em>

AnnyKZ [126]3 years ago

5 0

An object moving in a circular path with constant speed experiences centripetal acceleration.

Centripetal Acceleration- “the rate of change of tangential velocity”

“The direction of the centripetal acceleration is always inwards along the radius vector of circular motion.”

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How much time would it take to go up to the moon and back

marusya05 [52]

That completely depends on your speed and the trajectory (path) you choose.

The Apollo missions took about 3 days each way.

The New Horizons spacecraft passed the moon within a couple of hours after it was launched.

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3 years ago

Read 2 more answers

The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr

WARRIOR [948]

In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
$y_n= \frac{n \lambda D}{a}$ (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
$\lambda$ is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem,
$D=37.0 cm=0.37 m$
$\lambda=530 nm=5.3 \cdot 10^{-7} m$
while the distance between the first and the fifth minima is
$y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m$ (2)

If we use the formula to rewrite $y_5, y_1$ , eq.(2) becomes
$\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m$
Which we can solve to find a, the width of the slit:
$a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}= 1.57 \cdot 10^{-3} m=1.57 mm$

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4 years ago

A ball of plasticine is released from rest at height of 2.2 m above the ground. After touching the ground, the plasticine ball c

Anna35 [415]

The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²

The direction of the acceleration of the ball is downwards

The given parameters

initial velocity of the ball, u = 0

height above the ground, h = 2.2 m

time of motion of the ball, t = 96 ms = 0.096 s

The magnitude of the acceleration of the ball while coming to rest is calculated as;

let the downwards direction of the acceleration be positive

$h = ut + 0.5 at^2\\\\h = 0 + 0.5at^2\\\\h = 0.5 at^2\\\\a = \frac{h}{0.5t^2} \\\\a = \frac{2.2}{0.5 \times 0.096^2} \\\\a = 477.43 \ m/s^2$

The direction of the acceleration of the ball is downwards

Learn more here: brainly.com/question/15407740

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2 years ago

Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both

o-na [289]

Answer:

-True - True - true - false -false - false

Explanation:

True The flow depends only on the charge into the surface, not on the relative position
True The two vectors are radial, so their relative direction do not changes
True It just depends on the charge inside
False, it only depends on the charge, not on the form from the integration surface
False, because if it has a load inside it can be considered in the center, but if the load is outside the flow lines change direction with respect to the surface
False The flow depends only on the load inside, not on its position

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3 years ago

How ocean currents effect temperature and the amount of moisture of the air mass above coastlines

GarryVolchara [31]

Hotter ocean tempatures mean more moisture in the dense air mass

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3 years ago