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VLD [36.1K]
3 years ago
6

A load of 54 N attached to a spring that ishanging vertically stretches the spring 0.15 m.What is the spring constant?Answer in

units of N/m.
Physics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

300 N/m

Explanation:

given,

Load attached to the spring, W = 54 N

length of stretch of the spring, x = 0.15 m

spring constant= ?

Force applied on the spring is calculated by the equation

F = k x

where k is the spring constant

x is the displacement of the spring due to applied load

now,

54 = k × 0.15

k = \dfrac{54}{0.15}

k =300\ N/m

hence, the spring constant is equal to 300 N/m

myrzilka [38]3 years ago
6 0

Answer: The spring constant is 360 N/m

Explanation:

To calculate the spring constant, we use the equation:

F=kx       ......(1)

where,

F = force exerted on the spring = 54 N

k = spring constant = ?

x = length of the spring = 0.15 m

Putting values in equation 1, we get:

54N=k\times 0.15m\\\\k=\frac{54N}{0.15m}=360N/m

The spring constant is 360 N/m

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