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VLD [36.1K]
4 years ago
6

A load of 54 N attached to a spring that ishanging vertically stretches the spring 0.15 m.What is the spring constant?Answer in

units of N/m.
Physics
2 answers:
beks73 [17]4 years ago
8 0

Answer:

300 N/m

Explanation:

given,

Load attached to the spring, W = 54 N

length of stretch of the spring, x = 0.15 m

spring constant= ?

Force applied on the spring is calculated by the equation

F = k x

where k is the spring constant

x is the displacement of the spring due to applied load

now,

54 = k × 0.15

k = \dfrac{54}{0.15}

k =300\ N/m

hence, the spring constant is equal to 300 N/m

myrzilka [38]4 years ago
6 0

Answer: The spring constant is 360 N/m

Explanation:

To calculate the spring constant, we use the equation:

F=kx       ......(1)

where,

F = force exerted on the spring = 54 N

k = spring constant = ?

x = length of the spring = 0.15 m

Putting values in equation 1, we get:

54N=k\times 0.15m\\\\k=\frac{54N}{0.15m}=360N/m

The spring constant is 360 N/m

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A sheet of glass having an index of refraction of 1.49 is to be coated with a film of material having an index of refraction of
Blababa [14]

Answer:

the required minimum thickness is 179.19 nm

Explanation:

Given the data in the question;

Refraction index of air n₁ = 1

Refraction index of sheet n₂ = 1.49

Refraction index of film n₃ = 1.62

wavelength of green light λ = 534 nm

In the data given, n₂ > n₃

so, this case has no pie-phase shift,

the condition for constructive interference will be;

mλ = 2Ln₂

L = mλ / 2n₂

so we substitute

L = m(534) / 2( 1.49 )

L = m( 534/ 2.98 )

L = m( 179.19 nm )

so for minimum value of L,

let m = 1

such that, L_{min will be;

L_{min = 1 × ( 179.19 nm )

L_{min = 179.19 nm

Therefore, the required minimum thickness is 179.19 nm

8 0
3 years ago
A lunar lander is descending toward the moon's surface. Until the lander reaches the surface, its height above the surface is gi
miv72 [106K]

The question is incomplete. Here is the complete question:

A lunar lander is descending toward the moon’s surface. Until the lander reaches the surface, its height above the surface of the moon is given by y(t)=b−ct+dt2, where b = 800 m is the initial height of the lander above the surface, c = 60.0 m/s, and d=1.05m/s2 .  

(a) What is the initial velocity of the lander, at t = 0?  

(b) What is the velocity of the lander just before it reaches the lunar surface?

Answer:

(a) - 60 m/s

(b)    - 15.48 m/s

Explanation:

part (a)

In order to find initial velocity at time t = 0 we need to <em>differentiate </em>the expression for height with respect to time. The expression of height is given in the question.

Velocity = <em>dh / dt </em>

velocity = <em>d </em>(b−ct+dt²) / <em>dt </em>

<em></em>

after <em>differentiating </em>with respect to t  we get

velocity = - c + 2dt  

substituting the value of c, d and t.

velocity = - (60) + 2 (1.05) (0)

velocity = - 60 m/s  (Answer)

part (b)

We can find the answer of velocity by first finding the time taken to reach the lunar surface.

Just before it reaches the lunar surface means that its height above the surface of moon is about to become 0. We can find time of the journey by equating the expression of height above the moon with 0.

y(t) = b−ct+dt²

y(t) = 0

b-ct+dt² = 0

rearranging the equation

dt² – ct + b = 0

This is a quadratic equation. We can use quadratic formula to solve the equation for time.

Using the equation

t = (c ± √(c² – 4 db)) / 2d

where,

d =  1.05

c = 60.0

b = 800

The answers come out to be

t = 21.2 sec or t = 35.9 sec

By using the expression of velocity found above (part ‘a’) we can find the value of velocity

velocity = - c + 2dt  

velocity = - 60 + 2 (1.05) (21.2)

velocity = - 15.48 m/s  (Answer)

OR

v = - 60 + 2 (1.05)(35.9)

v = 15.39 m/s

We neglect second answer v = 15.39 m/s because we know that velocity cannot be positive in this case as the lunar lander is moving towards moon away from earth.

5 0
4 years ago
In the graph, during which time period does the particle undergo the greatest displacement?
VMariaS [17]
I'm not very good with Physics but of what I do know I'd go with point                   B / 4seconds 

I apologize in advance if that is incorrect.
5 0
4 years ago
5. A baseball player bats a ball with a force of 1,000 N. The ball exerts a reaction force against the bat
Annette [7]

<u>Explaining the concept:</u>

Reaction force is the equal and opposite force applied by an object after we apply some force to it

This is explained in the Newton's Third Law of Motion, which says: <em>"For every action, there is an equal and opposite reaction"</em>

This means that any force we apply on an object, it applies the same force on us

<u>Reaction Force exerted by the ball:</u>

We now know what a reaction force is. Now looking at the scenario, we can see that the player applied a force of 1000N on the ball using his bat

The ball will also apply an equal and opposite force on the Bat,

So, the ball will apply a force of 1000N on the Bat

Therefore, Option C is correct

7 0
3 years ago
1. One night, while Isaiah was in his bedroom playing Xbox, Isaiah's mom decided to
Lilit [14]

it wont let me send it with my drawing

5 0
3 years ago
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