Answer:570.54 N
Explanation:
Given
mass of man=76 kg
As man is standing over inclined building therefore
its weight has two components i.e. sin and cos component
Force perpendicular to inclined wall
F=570.54 N
Answer:
51.82
Explanation:
First of all, let's convert both vectors to cartesian coordinates:
Va = 36 < 53° = (36*cos(53), 36*sin(53))
Va = (21.67, 28.75)
Vb = 47 < 157° = (47*cos(157), 47*sin(157))
Vb = (-43.26, 18.36)
The sum of both vectors will be:
Va+Vb = (-21.59, 47.11) Now we will calculate the module of this vector:
Answer:
If child weight is equal to rope force then child will move with uniform speed
or we can say that the child will remain at rest in his position
Explanation:
As we know that child is hanging by rope
so here there will be two forces on the child
1) Weight or gravitational force which act vertically downwards
2) Tension in the rope which act vertically upwards
Now if child will accelerate upwards then tension force must be more than the weight of the child
If tension force is less than the weight then child will decelerate and his speed will decrease
if tension force is equal to child weight then in that case the child will remain at rest or it will move with same speed
Answer:
Positions in Hockey: 6 players for each team on the ice
1 Goalie – the player in the goal who tries to stop the puck from going in the net.
1 Center – plays in between the two wings and is usually the best passer on the team
2 Wings – offensive players who plays on both sides of the center. They are usually goal scorers
2 Defensemen – main job is to play defense and help defend the goal
Passing Cues
1. Stick blade faces target
2. Puck in center of blade
3. Transfer weight rear to front as you pass
4. Use wrist movement to drive the puck
5. Follow through at target
Receiving Cues:
1. athletic position
2. catch puck with middle of blade and control
3. slow the puck when it contacts the stick by giving with it
Explanation:
