1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artyom0805 [142]
3 years ago
8

Mutations that neither benefit nor harm the organisms have blanks effect on the organisms survival

Physics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

hope this helps :)

sasho [114]3 years ago
8 0

Mutations that neither benefit nor harm the organisms have blanks effect on the organisms survival

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

You might be interested in
The speed of a wave on a violin A string is 288 m/s and on the G string is 128 m/s. The force exerted on the ends of the string
Katyanochek1 [597]

Answer:

\dfrac{\mu_A}{\mu_G}=0.197

Explanation:

given,

Speed of a wave on violin A = 288 m/s

Speed on the G string = 128 m/s

Force at the end of string G  = 110 N

Force at the end of string A = 350 N

the ratio of mass per unit length of the strings (A/G). = ?

speed for string A

 v_A = \sqrt{\dfrac{F_A}{\mu_A}}.......(1)

speed for string G

 v_G = \sqrt{\dfrac{F_G}{\mu_G}}........(2)

Assuming force is same in both the string

now,

dividing equation (2)/(1)

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\dfrac{F_G}{\mu_G}}}{\sqrt{\dfrac{F_A}{\mu_A}}}

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{128}{288}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{\mu_A}{\mu_G}=0.197

5 0
3 years ago
Does voltage remain the same throughout a series circuit
seropon [69]

It depends on the circuit. Sometimes it becomes a bit weaker, sometimes it stays the same.

6 0
3 years ago
Read 2 more answers
What is the peacocks displacement from 2 to 3 seconds
mash [69]
1.5 second difference
7 0
2 years ago
which of the following statements best explains how consumers determine growth in technological areas
Mrac [35]
If these were the missing choices:

a)      Consumers fill out questionnaires concerning their need for new products.

b)      Consumers vote for politicians who decide which kind of research to support

c)       Consumers decide what to buy and what not to buy

d)      Consumers influence the decisions of private foundations by deciding where to donate money.


My answer would be: c)       <span>Consumers decide what to buy and what not to buy</span>

Every growth is based on the demand of the people. If a good or service is needed then its demand will increase. If a good or service is not needed then its demand will decrease until such time that said good or service will be eliminated. 

6 0
3 years ago
What happens to the bulb when the battery changes from 1.5V to 9v?
timofeeve [1]

Answer:

it gets brighter because the volta increases

4 0
3 years ago
Other questions:
  • What is a virgin i dk
    15·1 answer
  • Witch best describes the motion of the object between 1 and 4 seconds
    12·1 answer
  • 7. Thermal energy is the
    11·1 answer
  • How did rutherford's experiment show that thomson's plum pudding model was incorrect?
    15·1 answer
  • Which of the following careers would require a degree in physics?
    6·1 answer
  • A car is moving at high speed along a highway when the driver makes an emergency braking. The wheels become locked (stop rolling
    8·1 answer
  • You are designing a solenoid to produce a 2.0-kG magnetic field. You wish to wrap your insulated wire uniformly around a cardboa
    11·1 answer
  • If the water measures -5 feet at low tide and 3ft at high tide what is the tidal range ​
    15·1 answer
  • The free-body diagram of a crate is shown.
    14·2 answers
  • Use the Figure 1 and decide which swithes should be turned "on" position in order to get the circuit given in Figure 2.​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!