Complete question:
Two parallel 3.0-meter long wires conduct current. The current in the top wire is 12.5 A and flows to the right. The top wire feels a repulsive force of 2.4 x 10^-4 N created by the interaction of the 12.5 A current and the magnetic field created by the bottom current (I). Find the magnitude and direction of the bottom current, if the distance between the two wires is 40cm.
Answer:
The bottom current is 12.8 A to the right.
Explanation:
Given;
length of the wires, L = 3.0 m
current in the top wire, I₁ = 12.5 A
repulsive force between the two wires, F = 2.4 x 10⁻⁴ N
distance between the two wires, r = 40 cm = 0.4 m
The repulsive force between the two wires is given by;
Where;
I₂ is the bottom current
The direction of the bottom current must be in the same direction as the top current since the force between the two wires is repulsive.
Therefore, the bottom current is 12.8 A to the right.
The sentence can be completed as follows:
"Electricity is the movement of charges from one atom to another along a conductor."
The movement of the the charges is due to the presence of a potential difference across the conductor, which pushes the charges. More specifically, in normal conductors, the carriers of electricity are the electrons. Therefore we can rewrite the sentence as
"Electricity is the movement of electrons from one atom to another along a conductor."
Answer:
C. Quadruple the intensity
Explanation:
The intensity of the sound is proportional to square of amplitude of the sound.
I ∝ A²
When the given sound is twice loud as the initial value, then the new amplitude is twice the former.
A₂ = 2A₁
Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity
Answer:
I think C
Explanation:
Since the bus is moving away from John.
{C - V}.
<h2>Hey there!</h2>
The Force "F" applied on the unit electric charge "q" at a point describes the electric field.
<h3>☆ Formula to find electric charge:</h3>
<h2>Hope it helps </h2>
