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Inga [223]
3 years ago
12

If the speed of light in air is 3.00 · 108 m/s (approximately equal to that in a vacuum) and the speed of light in water is 2.25

· 108 m/s, what is the index of refraction of water?
Physics
2 answers:
podryga [215]3 years ago
7 0

Answer: 1.333

Explanation:

Index of refraction= n=c/v

Where c is the speed of light in vacuum and v is the speed of light in material ( water) in this case.

n = 3.00.108/2.25.108

n =3.00/2.25

n = 1.333

Approximately 1.33

There is no unit because m/s cancels out m/s

Natasha_Volkova [10]3 years ago
3 0
N= velocity in vacuum/velocity in water 
n=3.00*10⁸m/s/2.25 *10⁸m/s= 3.00/2.25 ≈ 1.33

n ≈ 1.33
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3 years ago
The speed of sound in air is approximately 350 m/s. You are sitting in a canyon with cliffs 525 m from you. You clap your hands.
Wewaii [24]

Answer:

3 s.

Explanation:

Echo is defined as the repetition of a sound produced by the reflection of sound waves from an obstructing surface like a wall, mountain etc.

v = f*lambda

Where,

Lambda = wavelength of the wave

f = frequency of the wave = 1/t

v = velocity of the wave.

Distance there and back = initial ditance * 2

= 525 x 2

= 1050.

Time taken, t = lamda/velocity

= 1050 / 350

= 3 s.

So the delay is 3 seconds.

3 0
3 years ago
Where should an object be placed in front of a concave mirror’s principal axis to form an image that is real, inverted, larger t
malfutka [58]
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Read 2 more answers
50. A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 335 kV. The secondar
Sedaia [141]

Answer:

Explanation:

a )  The transformer steps  up  the voltage from 12000 V  to 335000 V . Voltage in primary is 12000 V and in the secondary it is 335000 V in old transformer

If n₁ be no of turns in primary coil and n₂ be no of turns in secondary coils

the formula is

n₂ / n₁ = voltage in secondry / voltage in primary

n₂ / n₁ = 335000 / 12000

ratio of turns  in old transformer

= 27.9

ratio of turns  in new transformer

n₃ / n₁ = 750 / 12 ( n₃ is no of turns in the  secondary of new transformer )

= 62.5

T he ratio of turns in the new secondary compared with the old secondary

n₃ / n₂ = 62.5 / 27.9

= 2.24

b ) Current in secondary / current in primary

= turns in primary / turns in secondary

current output ratio of old

= Current in secondary / current in primary

= n₁ / n₂

= 12 / 335

= .03582

current output ratio of new

= Current in secondary / current in primary

= n₁ / n₃

= 12 / 750  

= .016

The ratio of new current output to old output (at 335 kV) for the same power

= .016 / .03582

= .4466

c ) power loss in new

=  (current in secondary )² x resistance of secondary

=( .016 x current in primary )² x R

= 2.56 X 10⁻⁴ X ( current in primary )² x R

power loss in old  

=  (current in secondary )² x resistance of secondary

=( .03582 x current in primary )² x R

= 12.83 X 10⁻⁴ X ( current in primary )² x R

ratio of new line power loss to old

= 2.56 / 12.83

= .199

7 0
3 years ago
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
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