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Valentin [98]
3 years ago
9

If a sound travels 343m/s through air and has a frequency of 800Hz, what would the wavelength be of the same sound traveling thr

ough water 500m/s with the same frequency?
Physics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

0.625m

Explanation:

Now Velocity of a wave ,V = frequency × wavelength

Wavelength =velocity /frequency

=500/800 =0.625m

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Find the length of an arc with a radius of 6.0m swept across 2.5 radians.
soldier1979 [14.2K]

Hello!

In terms of an arc length, radians is the measurement of an arc length in terms of the original radius. This arc length is 2.5 radians, so we multiply it by our original radius.

2.5(6)=15

Therefore, the arc length is 15 meters.

I hope this helps!


7 0
4 years ago
Think about the mice shown below. Using the space below numbered 1, describe what is happening from figure 1 to 3.​
UkoKoshka [18]

Answer: Natural selection is taking place.

Explanation:

As you can see, the lighter colored mice are more visible than their surroundings, so the hawk picks them off one by one. the brown mice on the other hand are less visible, blending in with their surroundings, so they are successful, and pass on the genes that allow them to survive better.

- anonymous

8 0
3 years ago
Give an example in which a small force exerts a large torque. give another example in which a large force exerts a small torque.
goldenfox [79]
<span>Since the torque involves the product of force times lever arm, a small force can exert a greater torque than a larger force if the small force has a large enough lever arm.

With a large force exerts a small torque is a gate, hinged in its vertical line (axis). When pushed from a point near to the hinge, a very large amount is needed to open the gate.
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3 0
3 years ago
Read 2 more answers
A ride at an amusement park moves the riders in a circle at a rate of 6.0 m/s. If the radius of the ride is 9.0 meters, what is
NikAS [45]
<span>4.0 m/s2


it's 9 squared divided by 6</span>
8 0
3 years ago
Read 2 more answers
Choose all facts that increase the orbital velocity of a vessel around planet B. Bigger mass of planet B smaller mass of planet
telo118 [61]

Answer:

- Bigger mass of planet B  

- orbiting closer to planet B

Explanation:

The orbital velocity of the vessel around the planet can be found by equalizing the force of gravity between the vessel and the planet and the centripetal force:

G\frac{mM}{r^2}=m\frac{v^2}{r}

where

G is the gravitational constant

m is the mass of the vessel

M is the mass of the planet

r is the distance between the vessel and the centre of the planet

v is the orbital velocity of the vessel

Re-arranging the formula, we find an expression for v:

v=\sqrt{\frac{GM}{r}}

We see that:

- the bigger the mass of the planet, M, the bigger the velocity

- the bigger the distance between the vessel and the planet, r, the smaller the velocity

So, the correct choices that increase the orbital velocity are:

- Bigger mass of planet B  

- orbiting closer to planet B

6 0
3 years ago
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