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3 years ago

When conduction electrons pass through a device with resistance, which describes their energy?

Physics

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

Answer:

a) their potential energy increases.

Explanation:

Ohm's Law is

R= V/I

Where R= Resistance

V= potential difference or potential energy

I= current or conduction electron flow rate

Clearly R and V are directly proportional i-e Potential energy increases with resistance.

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A 5,000 kg truck moving at 8 m/s has the same momentum as a 2,500 kg car. What is the velocity of the car?

rodikova [14]

Answer:

16 m/s.

Explanation:

The following data were obtained from the question:

Mass of truck = 5000 Kg

Velocity of truck = 8 m/s

Mass of car = 2500 kg

Velocity of car =..?

Next, we shall determine the momentum of the truck. This can be obtained as follow:

Mass of truck = 5000 Kg

Velocity of truck = 8 m/s

Momentum of truck =.?

Momentum = mass × velocity

Momentum = 5000 × 8

Momentum of the truck = 40000 Kg.m/s

Finally, we shall determine the velocity of the car as follow:

From the question given above, we were told that the car and truck has the same momentum.

This implies that:

Momentum of the truck = momentum of car = 40000 Kg.m/s

Thus, the velocity of the car can be obtained as shown below:

Mass of car = 2500 kg

Momentum of the car = 40000 Kg.m/s

Velocity of car =..?

Momentum = mass × velocity

40000 = 2500 × velocity

Divide both side by 2500

Velocity = 40000/2500

Velocity = 16 m/s

Therefore, the velocity of the car is 16 m/s.

5 0

3 years ago

A proton, an electron, and a helium nucleus all move at speed v . Rank their de Broglie wavelengths from largest to smallest.

Varvara68 [4.7K]

Ranking of de Broglie wavelengths from largest to smallest is electron > proton > helium

De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter.
From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship

De Broglie's relationship is given by $\lambda=\frac{h}{mv}$ .....(1) , where λ is known as de Broglie wavelength and m is mass , v is velocity , h = Plank’s constant.

From equation (1) wavelength and mass has an inverse relation .

Mass of helium is 4 times the mass of the proton and proton has a greater mass than electron.

According to equation (1) , less the mass higher will be the wavelength

Hence electron having less mass have higher wavelength and then proton and then helium having large mass will have less wavelength .

Thus, order should be electron > proton > helium .

Learn about de brogile wavelength more here :

brainly.com/question/16595523

#SPJ4

8 0

1 year ago

When the displacement in SHM is equal to 1/3 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b

Nesterboy [21]

Answer:

Explanation:

Given

Displacement is $\frac{1}{3}$ of Amplitude

i.e. $x=\frac{A}{3}$ , where A is maximum amplitude

Potential Energy is given by

$U=\frac{1}{2}kx^2$

$U=\frac{1}{2}k(\frac{A}{3})^2$

$U=\frac{1}{18}kA^2$

Total Energy of SHM is given by

$T.E.=\frac{1}{2}kA^2$

Total Energy=kinetic Energy+Potential Energy

$K.E.=\frac{1}{2}kA^2 -\frac{1}{18}kA^2$

$K.E.=\frac{8}{18}kA^2$

Potential Energy is $\frac{1}{8}$ th of Total Energy

Kinetic Energy is $\frac{8}{9}$ of Total Energy

(c)Kinetic Energy is $0.5\times \frac{1}{2}kA^2$

$P.E.=\frac{1}{4}kA^2$

$\frac{1}{2}kx^2=\frac{1}{4}kA^2$

$x=\frac{A}{\sqrt{2}}$

7 0

3 years ago

Read 2 more answers

A 320-kg satellite experiences a gravitational force of 800 N. What is the radius of the satellite’s orbit? What is its altitude

Westkost [7]

Answer:

Radius of orbit = 3.992 × $10^{7}$ m

Altitude of Satellite =33541.9× m

Explanation:

Formula for gravitational force for a satellite of mass m moving in an orbit of radius r around a planet of mass M is given by;

$F= G\frac{m M}{r^{2} }$

Where G = Gravitational constant = 6.67408 × 10-11 $\frac{m^{3} }{Kg sec^{2} }$

We are given

F= 800 N

m = 320 Kg

M = 5.972 × $10^{24}$ Kg

G = 6.67408 × 10-11 $\frac{m^{3} }{Kg sec^{2} }$

We have to find radius r =?

putting values in formula;

==> 800 =6.67408 × $10^{-11}$ × 320 × 5.972 × $10^{24}$ / $r^{2}$

==> 800= 39.8576 × $10^{13}$ × 320 / $r^{2}$

==> 800 = 12754.43 × $10^{13}$ / $r^{2}$

==> $r^{2}$ = 12754.43 × $10^{13}$ /800

==> $r^{2}$ =15.94 × $10^{13}$

==> r = 3.992 × $10^{7}$ m

==> r = 39920× $10^{3}$ m

This is the distance of satellite from center of earth. To find altitude we need distance from surface of earth. So we will subtract radius of earth from this number to find altitude.

Radius of earth =6378.1 km = 6378.1 × $10^{3}$ m

Altitude = 39920× $10^{3}$ - 6378.1 ×

3 0

3 years ago

A 30.0 kg box is placed on a 3.00 m tall shelf. What how much work was done on the box?

Kruka [31]

Answer:

W = 882.9[J]

Explanation:

In order to be able to calculate the work, we must first calculate the force necessary to lift the box. Since the necessary force is equivalent to the weight of the box, we can determine the weight of the box by means of the product of mass by gravitational acceleration.

$w = m*g\\$

where:

w = weight [N]

m = mass = 30 [kg]

g = gravity acceleration = 9.81 [m/s²]

$w = 30*9.81\\w = 294.3 [N]$

Now, the work can be calculated multiplying the force (weight) by the distance [m]

$W = w*d\\W = 294.3*3\\W=882.9[J]$

6 0

3 years ago