what is the volume in cubic meter and in cubic decimeter of 2.0mol of nitrogen on gas at 1000c and 100,000pa? (R=8.31j/molk)
1 answer:
Given parameters:
Number of moles of Nitrogen = 2.0mole
Temperature of the gas = 1000c
Pressure on the gas = 100000Pa
Gas constant R = 8.31J/molK = 0.082atmdm³mol⁻¹k⁻¹
Unknown:
Volume in cubic meter and cubic decimeter = ?
Solution:
The ideal gas law is given as;
PV = nRT
where P is the pressure on the gas
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the temperature of the gas
Let us convert to appropriate units;
1000°C to K;
K = 1000 + 273 = 1273K
100000Pa to atm;
101325Pa = 1atm
100000Pa = 0.99atm
Input the parameters and solve for the unknown;
0.99 x V = 2 x 0.082 x 1273
V = 210.9dm³
to m³;
1000dm³ = 1m³
210.9dm³ = = 0.21m³
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Answer:
Explanation:
Given:
Pressure = 745 mm Hg
Also, P (mm Hg) = P (atm) / 760
Pressure = 745 / 760 = 0.9803 atm
Temperature = 19 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (19 + 273.15) K = 292.15 K
Volume = 0.200 L
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K
⇒n = 0.008174 moles
From the reaction shown below:-
1 mole of react with 2 moles of
0.008174 mole of react with 2*0.008174 moles of
Moles of = 0.016348 moles
Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)
So,