Answer:
Option C. 13.5 atm
Explanation:
From the question given above, the following data were obtained:
Pressure of Neon (Pₙₑ) = 4.1 atm
Pressure of Argon (Pₐᵣ) = 3.2 atm
Pressure of nitrogen (Pₙ₂) = 6.2 atm
Total pressure (Pₜ) =?
The total pressure in the container can be obtained by adding the pressure of the individual gases. This is illustrated below:
Pₜ = Pₙₑ + Pₐᵣ + Pₙ₂
Pₜ = 4.1 + 3.2 + 6.2
Pₜ = 13.5 atm
Therefore, the total pressure in the container is 13.5 atm
<h3>
Answer:</h3>
Temperature is 529.164 K
<h3>
Explanation:</h3>
We are given
Number of moles of Ne (n) = 0.019135 moles
Volume (V) = 878.3 mL
Pressure (P) = 0.946 atm
We are required to calculate the temperature;
We can do this using the ideal gas law equation which is;
PV = nRT, where P is the pressure, n is the number of moles, V is the volume, R is the ideal gas constant (0.082057 Latm/mol/K) and T is the temperature.
From the equation;
Therefore, the temperature will be 529.164 K.
PH = -log [H+]
pH = -log (1.0x10^-4) = -(-4) = 4 or A
Answer:
B
Explanation:
alkene is no polar compounds
and insoluble in water
The answer is: the pressure inside a can of deodorant is 1.28 atm.
Gay-Lussac's Law: the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.
p₁/T₁ = p₂/T₂.
p₁ = 1.0 atm.; initial pressure
T₁ = 15°C = 288.15 K; initial temperature.
T₂ = 95°C = 368.15 K, final temperature
p₂ = ?; final presure.
1.0 atm/288.15 K = p₂/368.15 K.
1.0 atm · 368.15 K = 288.15 K · p₂.
p₂ = 368.15 atm·K ÷ 288.15 K.
p₂ = 1.28 atm.
As the temperature goes up, the pressure also goes up and vice-versa.
