Let v is the velocity of the stone after 3 seconds have passed. It is moving down under the action of gravity. So, using the first equation of motion as :
v = 35 m/s
So, the final speed of the stone is 35 m/s. Hence, this is the required solution.
The solution for this problem is: Let u denote speed.
Equating momentum before and after collision: = 0.060 * 40 = (1.5 + 0.060) u = 2.4 = 1.56 u = 2.4 / 1.56 = 1.56 u / 1.56 = 1.6 m / s is the answer for this question. This is the speed after the collision.