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jasenka [17]
4 years ago
5

A weather balloon slowly expands as energy is transferred as heat from the outside If the average net pressure is air. 1.5 x 103

Pa and the balloon's volume increases by 5.4 x 10 5 m how much work is done by the expanding gas? What thermodynamic process does this situation resemble?
Physics
2 answers:
Anni [7]4 years ago
7 0
There is only one pressure this situation would be a "constant pressure" process. The work done by expanding gas is.
=p(delta V) = (1.5e3)(5.e3)(5.4e-5) N/m^2xm^3) N/m2xm^3= 8.1e-2 N-m ANS
Aleks04 [339]4 years ago
5 0

Answer:

8.1x10⁸ J

A pressure constant process.

Explanation:

The gas inside the balloon is gain heat from the surroundings and its volumes increase, but the pressure remains constant. So, it's a pressure constant process.

For this thermodynamic process, the work is the pressure multiplied by the volume variation:

W = 1.5x10³ x 5.4x10⁵

W = 8.1x10⁸ J

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Answer:

The focal length fe of the eyepiece is <em>2.86 cm</em>

Explanation:

Since we are given the telescope's magnification and the length of the tube, we can use the expressions

<em>M = f_o/fe (1)</em> and

<em>l = f_o + fe   (2)</em>

where

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  • l is the length of the tube
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Rearranging equation (2) to make f_o the subject of the formula, we get

<em>f_o = l - fe</em>

Substituting the above equation into equation (1) we get

<em>M = (l - fe)/fe ⇒ fe = l/(M +1)</em>

<em>                      ⇒ fe = 60/(20 + 1)</em>

                     ⇒ <em>fe  = 2.86 cm</em>

4 0
4 years ago
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Alchen [17]

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Explanation:

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Therefore, forces that are equal in size but opposite in direction are balanced.

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Answer:

Transform boundaries

Explanation:

I TOOK A TEST ON THIS QUESTION

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Lelu [443]
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