Question

A weather balloon slowly expands as energy is transferred as heat from the outside If the average net pressure is air. 1.5 x 103 Pa and the balloon's volume increases by 5.4 x 10 5 m how much work is done by the expanding gas? What thermodynamic process does this situation resemble?

Answer 1

There is only one pressure this situation would be a "constant pressure" process. The work done by expanding gas is.
=p(delta V) = (1.5e3)(5.e3)(5.4e-5) N/m^2xm^3) N/m2xm^3= 8.1e-2 N-m ANS

Answer 2

Answer:

8.1x10⁸ J

A pressure constant process.

Explanation:

The gas inside the balloon is gain heat from the surroundings and its volumes increase, but the pressure remains constant. So, it's a pressure constant process.

For this thermodynamic process, the work is the pressure multiplied by the volume variation:

W = 1.5x10³ x 5.4x10⁵

W = 8.1x10⁸ J