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jasenka [17]
3 years ago
5

A weather balloon slowly expands as energy is transferred as heat from the outside If the average net pressure is air. 1.5 x 103

Pa and the balloon's volume increases by 5.4 x 10 5 m how much work is done by the expanding gas? What thermodynamic process does this situation resemble?
Physics
2 answers:
Anni [7]3 years ago
7 0
There is only one pressure this situation would be a "constant pressure" process. The work done by expanding gas is.
=p(delta V) = (1.5e3)(5.e3)(5.4e-5) N/m^2xm^3) N/m2xm^3= 8.1e-2 N-m ANS
Aleks04 [339]3 years ago
5 0

Answer:

8.1x10⁸ J

A pressure constant process.

Explanation:

The gas inside the balloon is gain heat from the surroundings and its volumes increase, but the pressure remains constant. So, it's a pressure constant process.

For this thermodynamic process, the work is the pressure multiplied by the volume variation:

W = 1.5x10³ x 5.4x10⁵

W = 8.1x10⁸ J

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C) Contact

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The magnet requires almost direct <u>contact</u> with the fridge to start its magnetic properties.

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A pendulum oscillates 12 times in 4 seconds. what is the length of the pendulum?
seraphim [82]

Answer:

L = 2.8 cm

Explanation:

Period T = 4 / 12 = 1/3 s

T = 2π√(L/g)

L = (T/2π)²g

L = ((1/3)/2π)²9.8 = 0.02758... ≈ 2.8 cm

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mash [69]

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4 0
3 years ago
20. In a parallel RL circuit, 10 mA flows through the resistor and 4 mA flows through the inductor. What phase angle separates v
stellarik [79]

Answer:

Option D: 21.8 degrees

Explanation:

In a parallel RL circuit, the current in the resistor R and that in the inductor L are separated among themselves 90 degrees as illustrated in the attached image. In the image the current in the resistor is represented in orange, that of the inductor in blue, and the total current (vector addition of the previous two) is represented  in red, forming a certain angle (theta) with respect to the current in the resistor. The output voltage is the same as the input voltage as measured over the resistor R.

Therefore, the phase angle that separated output voltage and total current can be obtained using the fact that tan(phase angle) = \frac{I_l}{I_R} = \frac{x}{y} \frac{4}{10}, therefore the angle is the arctangent of 4/10:

arctang(\frac{4}{10} )= 21.801 degrees.

8 0
4 years ago
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A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
3 years ago
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