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cestrela7 [59]
2 years ago
9

The half-life of a strontium isotope is 25 years. How much of this particular isotope will remain after 100 years if the startin

g mass is 16 grams?
Chemistry
1 answer:
Phoenix [80]2 years ago
3 0

Answer:

1 gram

Explanation:

Half life = 25 years

Starting mass = 16 grams

Time = 100 years

Number of half lives = Time / Duration of Half life = 100 / 25 = 4

After first Half life;

Remaining mass = 16 / 2 =  8 g

After Second Half life;

Remaining mass = 8 / 2 =  4 g

After Third Half life;

Remaining mass = 4 / 2 =  2 g

After Fourth Half life;

Remaining mass = 2 / 2 = 1 g

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What floats on top of molten magma under the earth’s surface?.
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Explanation:

Earthquakes. are caused by the earth's crust, more specifically, tectonic plates that float on top of molten magma. These plates bump into each other. it's the answer Earthquakes.

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2 years ago
What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


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I hope it's helpful!

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