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3 years ago

9

A person walks briskly at 1.90 m/s .how much time will it take them to walk one mile?

1 answer:

Paladinen [302]3 years ago

5 0

As in question, the speed of person is given m/s whereas the distance he needs to cover is given in miles.

Formula to calculate the time,

$Distance = velocity \times time$

To get the correct answer, convert the distance in to miles.

$1 mile = (1\times1.6093)\times1,000=1,609.3$

Therefore,

$1,609.3 meters = 1.90 m/s \times time$

or

$time = \frac{1,609.3 m}{1.90 m/s}$

$time = 847 s$

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Light is an electromagnetic wave and travels at a speed of 3.00 × 108 m/s. The human eye is most sensitive to yellow-green light

Nimfa-mama [501]

Answer:

$f = 5.95 \times 10^{14} Hz$

Explanation:

As we know that the frequency of the wave is given as

$f = \frac{c}{\lambda}$

here we know that

$c = 3 \times 10^8 m/s$

also we know that

$\lambda = 5.04 \times 10^{-7} m$

now we have

$f = \frac{3 \times 10^8}{5.04 \times 10^{-7}}$

$f = 5.95 \times 10^{14} Hz$

6 0

2 years ago

When a 20-V emf is placed across two resistors in series, a current of 2.0 A is present in each of the resistors. When the same

ehidna [41]

Answer:

7.24 ohm

Explanation:

Let R1 and R2 are resistance of two resistors.

Emf=E=20 V

Current,I=2 A

Current,I'=10 A

We have to find the magnitude of the greater of the two resistances.

In series

$R=R_1+R_2$

$V=IR$

By using the formula

$20=2(R_1+R_2)$

$R_1+R_2=\frac{20}{2}=10$ ...(1)

In parallel

$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R}=\frac{R_2+R_1}{R_1R_2}$

$R=\frac{R_1R_2}{R_1+R_2}$

$20=10(\frac{R_1R_2}{R_1+R_2}$

$2=\frac{R_1R_2}{10}$

$R_1R_2=20$

$R_2=\frac{20}{R_1}$

Substitute the value

$\frac{20}{R_1}+R_1=10$

$R^2_1+20=10R_1$

$R^2_1-10R_1+20=0$

$R_1=\frac{10\pm\sqrt{(-10)^2-4(20)}}{2}$

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$R_1=\frac{10\pm 2\sqrt 5}{2}$

$R_1=\frac{10+2\sqrt 5}{2}=5+\sqrt 5=7.24 ohm$

$R_1=\frac{10-2\sqrt 5}{2}=2.76 ohm$

Substitute the value

$R_2=\frac{20}{7.24}=2.76 ohm$

$R_2=\frac{20}{2.76}=7.24 ohm$

Hence, the magnitude of the greater of the two resistance=7.24 ohm

8 0

3 years ago

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Based on Archimedes' principle, we know that if an object displaces a given weight of water, then the object is being buoyed up

Virty [35]

True. If the amount displaced is more than the mass, it floats. If the amount is less than the mass, it will sink.

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2 years ago

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A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is its radius? (The value of μ0 is 4π x 1

nevsk [136]

Answer:

A. 2.2*10^-2m

Explanation:

Using

Area = length x L/ uo xN²

So A = 0.7m * 25 x 10^-3H /( 4π x10^-7*

3000²)

A = 17.5*10^-3/ 1.13*10^-5

= 15.5*10^-2m²

Area= π r ²

15.5E-2/3.142 = r²

2.2*10^2m

Explanation:

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3 years ago

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KIM [24]

Answer:

volume is the correct answer

Explanation:

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2 years ago