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andrew-mc [135]
3 years ago
6

Can someone help me solve this please?

Mathematics
1 answer:
dybincka [34]3 years ago
5 0
I would help but its a picture and not words so i don't know how too help you sorry :(
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a)How many different ways can you allocate the 22 students to the projects?  =2300

b)  how many different ways can you allocate the 22 students to the projects=    286

Step-by-step explanation:

check attachment for detail explanations

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If 18-6x is 4 less than -8, what is the value of -3x?
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Step-by-step explanation:

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Step-by-step explanation:

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4 years ago
PLEASE HELPPP<br><br> Which expression is equivalent to
Anettt [7]

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Fourth option

Step-by-step explanation:

Given the expression in the picture:

Apply Power of Power Rule

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7 0
3 years ago
The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
3 years ago
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