Energy is absorbed so, the mass is increased.
energy is released so, the mass is increased
Answer:
Total cost = $40.25 (Approx)
Explanation:
Given:
Per ounce = $1.15
Number of student = 28
Each student eat = 0.035 kg
Find:
Total cost
Computation:
Total weight of candy = 28 × 0.035 kg
Total weight of candy = 0.98 kg
1 ounce = 0.028 kg (approx).
Total weight of candy = 0.98 kg / 0.028
Total weight of candy = 35 ounce (Approx)
Total cost = 35 × $1.15
Total cost = $40.25 (Approx)
Answer:
Explained below.
Explanation:
The difference between the two of them will be considered from their electrostatic potential maps.
First of all the major difference is that ammonia molecule(NH3) has a lone lone pair of electron on the N atom.
Due to the this lone pair of electron on the N - atom of ammonia, it's bond angle will be slightly lesser than that of ammonium ion.
Therefore, In the electrostatic potential map of NH3, the charge distribution will not be symmetrical for the fact that there is electron rich N atom and so the N atom will be more red than the 3 hydrogen atoms (H atoms).
Whereas, the electrostatic potential map of NH4+ (ammonium ion) will be symmetrical due to the even/symmetrical distribution of all the 4 hydrogen atoms surrounding the central Nitrogen atom.
Also, the Nitrogen atom here in ammonium ion will have a lower electron density than the Nitrogen atom that's present in ammonia molecule due to the bonding existing between the lone pair electron and the Hydrogen atom
<h3>Yes mam it is tinder .....</h3>
Answer:
A)glyceraldehyde 3-phosphate dehydrogenase reaction,
B)Thehexose bisphosphate that accumulates is fructose 1,6-bisphosphate
C)glyceraldehyde 3-phosphate dehydrogenase reaction to yield an acyl arsenate
Explanation:
The fermentation of ethanol in yeast has the following overall equation Glucose 2ADP 2Pi88n2 ethanol 2CO22ATP 2H2O which makes it clear that phosphate is required for the continued operation of glycolysis and formation of ethanol . In extracts to which glucose is added, fermentation proceeds until ADP and Pi(present in the extracts) are exhausted.(a)Phosphate is required in the glyceraldehyde 3-phosphate dehydrogenase reaction, and glycolysis will stop at this step when Piis exhausted. Because glucose remains, it will be phosphorylated by ATP, but Piwill not be released.(b)Fermentation in yeast cells produces ethanol and CO2rather than lactate . Without these reactions (in the absence of oxygen), NADH would accumu-late and no new NADwould be available for further glycolysis ). Thehexose bisphosphate that accumulates is fructose 1,6-bisphosphate; in terms of energet-ics, this intermediate lies at a “low point” or valley in the pathway, between the energy-input reactions that precede it and the energy-payoff reactions that follow.(c)Arsenate replaces Piin the glyceraldehyde 3-phosphate dehydrogenase reaction to yieldan acyl arsenate, which spontaneously hydrolyzes. This prevents formation of fructose1,6-bisphosphate and ATP but allows formation of 3-phosphoglycerate, which continuesthrough the pathway.
