1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nat2105 [25]
2 years ago
13

In 1906 Harden and Young, in a series of classic studies on the fermentation of glucose to ethanol and CO2 by extracts of brewer

's yeast, made the following observations.
(A) Inorganic phosphate was essential to fermentation; when the supply of phosphate was exhausted, fermentation ceased before all the glucose was used.
(B) During fermentation under these conditions, ethanol, CO2, and a sugar phosphate accumulated.
(C) When arsenate was substituted for phosphate, no sugar phosphate acumulated, but the fermentation proceeded until all the glucose was converted to ethanol and CO2.
Chemistry
1 answer:
aalyn [17]2 years ago
4 0

Answer:

A)glyceraldehyde 3-phosphate dehydrogenase reaction,

B)Thehexose bisphosphate that accumulates is fructose 1,6-bisphosphate

C)glyceraldehyde 3-phosphate dehydrogenase reaction to yield an acyl arsenate

Explanation:

The fermentation of ethanol in yeast has the following overall equation Glucose 2ADP 2Pi88n2 ethanol 2CO22ATP 2H2O which makes it clear that phosphate is required for the continued operation of glycolysis and formation of ethanol . In extracts to which glucose is added, fermentation proceeds until ADP and Pi(present in the extracts) are exhausted.(a)Phosphate is required in the glyceraldehyde 3-phosphate dehydrogenase reaction, and glycolysis will stop at this step when Piis exhausted. Because glucose remains, it will be phosphorylated by ATP, but Piwill not be released.(b)Fermentation in yeast cells produces ethanol and CO2rather than lactate . Without these reactions (in the absence of oxygen), NADH would accumu-late and no new NADwould be available for further glycolysis ). Thehexose bisphosphate that accumulates is fructose 1,6-bisphosphate; in terms of energet-ics, this intermediate lies at a “low point” or valley in the pathway, between the energy-input reactions that precede it and the energy-payoff reactions that follow.(c)Arsenate replaces Piin the glyceraldehyde 3-phosphate dehydrogenase reaction to yieldan acyl arsenate, which spontaneously hydrolyzes. This prevents formation of fructose1,6-bisphosphate and ATP but allows formation of 3-phosphoglycerate, which continuesthrough the pathway.

You might be interested in
Why a person bitten by a snake can not drink alcohol​
AfilCa [17]
Alcoholic liquors are harmful to persons bitten by venomous snakes." The alcohol acts first as a stimulant, speeding up the circulation, quickly distributing the poison through the body. When the effect wears off it becomes a depressant, lowering the victim's resistance,
8 0
2 years ago
An element belonging to the halogen family would be expected to have a ________ ionization energy and a ________ electron affini
nikklg [1K]
<span>An element belonging to the halogen family would be expected to have a large ionization energy and a large electron affinity.
Flourine, Chlorine, Bromine, Iodine and astatine are the elements that belongs to the halogen family and mostly they have high values of ionization energy. 
The amount of energy released when an electron is added to an atom or molecule to form a negative ion or anion is electron affinity.</span>Chlorine from this family has highest electron affinity.

8 0
3 years ago
At 25.0°c, a solution has a concentration of 3.179 m and a density of 1.260 g/ml. the density of the solution at 50.0°c is 1.249
oksano4ka [1.4K]

Answer: -

3.151 M

Explanation: -

Let the volume of the solution be 1000 mL.

At 25.0 °C, Density = 1.260 g/ mL

Mass of the solution = Density x volume

= 1.260 g / mL x 1000 mL

= 1260 g

At 25.0 °C, the molarity = 3.179 M

Number of moles present per 1000 mL = 3.179 mol

Strength of the solution in g / mol

= 1260 g / 3.179 mol = 396.35 g / mol (at 25.0 °C)

Now at 50.0 °C

The density is 1.249 g/ mL

Mass of the solution = density x volume = 1.249 g / mL x 1000 mL

= 1249 g.

Number of moles present in 1249 g = Mass of the solution / Strength in g /mol

= \frac{1249 g}{396.35 g/mol}

= 3.151 moles.

So 3.151 moles is present in 1000 mL at 50.0 °C

Molarity at 50.0 °C = 3.151 M

7 0
2 years ago
Is pyrophoric a chemical or physical property
Neporo4naja [7]

Answer:

Pyrophoricity is a property of metals and oxides of lower oxidation states, including radioactive ones, in which they spontaneously ignite during or after stabilization.

5 0
3 years ago
Find the volume of 20g of H₂ at STP<br><br>​
ANEK [815]

Answer:224

Explanation:

We should answer it with Stoichiometry

We say: 20 g H2× (1 mol/ 2g)× ( 22.4 lit/ 1 mol) = 224

Means: we have 20 grams and every 2g H2, equals to 1 mol of it and every 1 mol of H2, equals to 22.4 lit( because of STP)

hope you got this:)

6 0
2 years ago
Other questions:
  • How many moles of MgS2O3 are in 201g of the compound?
    15·1 answer
  • Which planet has the longest year and why ?
    12·2 answers
  • Calculate the volume of 2.5×10-4 moles of h2
    8·1 answer
  • The molar heat of vaporization for water is 10.79 kJ/mol. How much energy must be absorbed by 100 grams
    14·1 answer
  • Once alcohol is in the bloodstream, it will reach the brain in a few
    12·1 answer
  • A) How many grams of Cu(OH)2will precipitate when excess NaOH solution is added to 42.0mL of 0.641 M CuI2 solution?
    8·1 answer
  • Diffrent between bryophytes and pteriodphytes
    11·1 answer
  • Helpppppppppppppp pls ?
    15·1 answer
  • Water can keep engines operating at low temperatures. Which property of water most likely gives it this ability?
    11·1 answer
  • What type of front is depicted here? (60 Points)
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!