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Arisa [49]
4 years ago
9

What is the goal of the closing process? a.to end the accounting period with a profit b.to verify that all adjustments have been

made c.to make sure all temporary accounts have a zero balance d.to move all equity accounts to Retained Earnings
Mathematics
1 answer:
mamaluj [8]4 years ago
5 0

Answer:

C. To make sure all temporary accounts have a zero balance.

Step-by-step explanation:

The closing process is an accounting method applied at the end of the year with the purpose of ensuring that all accounts are ready for the preparation of financial statements, as well as the start of a new accounting year.

Temporary accounts are made permanent. Also, the accounts for the present year are zeroed. By so doing, only the current balance will be reflected in the new year accounts.

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HELP PLEASEEEE I WILL AWARD 100 POINTS ITS DUE ASAPPP<br> What is the equation for A(w)=?
skad [1K]

Answer:

390=W 195=L Area=76050

Step-by-step explanation:

You have two lengths and one width for your perimeter

P= 2L + W

you are given your perimiter 780

780= 2L + W

To solve for your maximum Width

780-2L=w

Area is L * W

A= (780-2L)*L

A= 780L - 2L^2

the derivitive of the Area

A' = 780-4L =0

add 4L to both sides

780=4L

divide by 4 on both sides

195=L

Bring back 780-2L=W and plug in what you now know is L

780-2(195)=W

780-390=W

390=W

7 0
3 years ago
In a survey of women in a certain country the mean height was 62.9 inches with a standard deviation of 2.81 inches answer the fo
Natasha2012 [34]

The question is incomplete. The complete question is :

In a survey of women in a certain country ( ages 20-29), the mean height was 62.9 inches with a standard deviation of 2.81 inches.  Answer the following questions about the specified normal distribution.  (a) What height represents the 99th percentile?  (b) What height represents the first quartile?  (Round to two decimal places as needed)

Solution :

Let the random variable X represents the height of women in a country.

Given :

X is normal with mean, μ = 62.9 inches and the standard deviation, σ = 2.81 inches

Let,

$Z=\frac{X - 62.9}{2.81}$ , then Z is a standard normal

a). Let the 99th percentile is = a

The point a is such that,

$P(X

$P \left( Z < \frac{a-62.9}{2.81} \right) = 0.99$

From standard table, we get : P( Z < 2.3263) =0.99

∴ $\frac{(a-62.9)}{281} = 2.3263$

  $a= (2.3263 \times 2.81 ) +62.9$

     = 6.536903 + 62.9

     = 69.436903

     = 69.5 (rounding off)

Therefore, the height represents the 99th percentile = 69.5 inches.

b). Let b = height represents the first quartile.

It is given by :

P( X < b) =0.25

$P \left( Z < \frac{(b-62.9)}{2.81} \right) = 0.25$

From the standard normal table,

P( Z < -0.6745) =0.99

∴ $\frac{(b-62.9)}{2.81}= 0.6745$

$b=(0.6745 \times 2.81) +62.9$

  = 1.895345 + 62.9

   = 64.795345

   = 64.8 (rounding off)

Therefore, the height represents the 1st quartile is 64.8 inches.

8 0
3 years ago
What is the perimeter of a square that has and area equal to 64??
egoroff_w [7]

Answer:12

Step-by-step explanation:

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3 years ago
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Plz help ill give brainliest
Lilit [14]

Answer:

C

Step-by-step explanation:

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3 years ago
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Stephano walks 2/5 miles is 1/4. What is stephano's speed in miles per hour
kupik [55]
The answerd is 3/9 bc 2/5+1/4 is 3/9
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4 years ago
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