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3 years ago

How can naural gas be manged so that we dont run out

1 answer:

5 0

<span>We don’t have to worry because in our current rate of use we have natural gas that is reserved to last 60-90 years. Although the total amount of natural isn’t increasing, the ability to find from new resources expands every day. We can now produce natural gas from deep deposits located beneath the surface of the earth, and in the deep ocean. Natural gas industries are also investing in alternative energy such as solar, wind, geothermal and biomass to make these energy resources more affordable and reliable.
</span>

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9. A 12 v battery is connected to four 5 ohm light bulbs. What is the equivalent

vlabodo [156]

20 ohms 5 ohms
12volts

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3 years ago

When low on gasoline, is it better to increase or decrease the speed of the vehicle? Explain.

sergiy2304 [10]

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3 years ago

A bullet is fired straight up from a gun with a

Katena32 [7]

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3 years ago

Read 2 more answers

Calculate the missing variable....

OlgaM077 [116]

Answer:

option b

Explanation:

from the given formula, s=d/t

make t the subject of the formula we have

t=d/s

5/100

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3 years ago

A charged particle enters a uniform magnetic field B with a velocity v at right angles to the field. It moves in a circle with p

alukav5142 [94]

A) d. 10T

When a charged particle moves at right angle to a uniform magnetic field, it experiences a force whose magnitude os given by

$F=qvB$

where q is the charge of the particle, v is the velocity, B is the strength of the magnetic field.

This force acts as a centripetal force, keeping the particle in a circular motion - so we can write

$qvB = \frac{mv^2}{r}$

which can be rewritten as

$v=\frac{qB}{mr}$

The velocity can be rewritten as the ratio between the lenght of the circumference and the period of revolution (T):

$\frac{2\pi r}{T}=\frac{qB}{mr}$

So, we get:

$T=\frac{2\pi m r^2}{qB}$

We see that this the period of revolution is directly proportional to the mass of the particle: therefore, if the second particle is 10 times as massive, then its period will be 10 times longer.

B) $a. f/10$

The frequency of revolution of a particle in uniform circular motion is

$f=\frac{1}{T}$

where

f is the frequency

T is the period

We see that the frequency is inversely proportional to the period. Therefore, if the period of the more massive particle is 10 times that of the smaller particle:

T' = 10 T

Then its frequency of revolution will be:

$f'=\frac{1}{T'}=\frac{1}{(10T)}=\frac{f}{10}$

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3 years ago