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romanna [79]
3 years ago
15

In a nucleotide, the nitrogenous base is attached to the sugar's _____ carbon and the phosphate group is attached to the sugar's

_____ carbon.
Chemistry
1 answer:
Anon25 [30]3 years ago
6 0

Answer:

1' and 5' carbon.

Explanation:

DNA is the genetic material of almost all the living organisms but exceptions are involved in case of some viruses that contains RNA as their genetic material.

The DNA consists of the nitrogenous base, dexoyribose pentose sugar and the phosphate group. The base is attached with the sugar on the 1' position. The phosphate group is linked with the sugar at 5 position of the dexoyribose sugar.

Thus, the correct answer is 1' and 5' carbon.

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When the Earth rotates on its axis, it prevents air currents from going in a straight line to the north and the south from the equator. It results in one of the effects of rotation of the Earth: the Coriolis Effect.

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What components are needed in a expeirment
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Independent and dependent variables and constants
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What is the process that changes one set of chemicals into another set of chemicals? A. cohesion B. hydrogen bonding C. chemical
diamong [38]
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3 0
3 years ago
Read 2 more answers
Mannoheptulose is a sugar found in avocados. If each C-C bond contains 76 kcal of energy and each C-H bond contains 91 kcal, how
nadya68 [22]

Answer:

Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal

Explanation:

The molecular formula of mannoheptulose is C₇H₁₄O₇.

The structure is as shown in the attachment below.

Number of C-C bonds present in mannoheptulose = 6

Number of C-H bonds present in mannoheptulose = 8

Since the each C-C bond contains 76 Kcal of energy,

Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal

Also, since each C-H bond contains 91 Kcal of energy;

amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal

Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal

6 0
3 years ago
This is very urgent please hurry!!?!!??!
yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

a =\frac{F}{m}

A) The box with a mass of 2kg

F = 8 N

a =\frac{8}{2}

a = 4 m/s2

B) The box with the mass of 4kg

a =\frac{8}{4}

a = 2 m/s2

C) The box with a mass of 6kg

a =\frac{8}{6}

a = 1.33 m/s2

D) The box with a mass of 8kg

a =\frac{8}{8}

a = 1 m/s2

3 0
3 years ago
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