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mojhsa [17]
3 years ago
15

In an aqueous solution of a certain acid with pka = 3.75 the ph is 2.82 . calculate the percent of the acid that is dissociated

in this solution. round your answer to significant digits.

Chemistry
1 answer:
Arturiano [62]3 years ago
8 0
Hello! Let me try to answer this :)

Thanks and please correct if there are any mistakes ^ ^

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The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat
Darya [45]

Answer:

Heat of fusion

Explanation:

The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat of fusion.

The formula for the heat of fusion is given by :

\Delta H=n\Delta H_{fus}

Where

n is no of moles

\Delta H_{fus} is molar heat of the substance

Hence, the correct answer is heat of fusion

8 0
2 years ago
If fluorine gas (F₂) occupies a volume of 45.5 L at a pressure of 850
pshichka [43]

Taking into account about the ideal gas law, the mass of fluorine gas is 63.2244 grams.

<h3>What is ideal gas law</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that occupies.
  • T is its temperature. The universal constant of ideal gases R has the same value for all gaseous substances.
  • R is the ideal gas constant.
  • n is the number of moles of the gas.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Mass of fluorine gas</h3>

In this case, you know:

  • P= 850 mmHg= 1.11842 atm (being 1 mmHg= 0.00131579 atm)
  • V= 45.5 L
  • T =100 °C= 373 K (being 0°C= 273 K)
  • R= 0.082 \frac{atm L}{mol K}
  • n= ?

Replacing in the ideal gas law:

1.11842 atm ×45.5 L = n×0.082 \frac{atm L}{mol K}× 373 K

Solving:

n= (1.11842 atm ×45.5 L)÷ (0.082 \frac{atm L}{mol K}× 373 K)

<u><em>n= 1.6638 moles</em></u>

The molar mass of F₂ is 38 g/mole. Then you can apply the folowing rule of three: If by definition of molar mass 1 mole of the compound contains 38 grams, 1.6638 moles of the compound contains how much mass?

mass= \frac{1.6638 molesx38 grams}{1 mole}

<u><em>mass= 63.2244 grams</em></u>

Finally, the mass of fluorine gas is 63.2244 grams.

Learn more about

the ideal gas law:

brainly.com/question/4147359

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

#SPJ1

7 0
1 year ago
When 7.80 mL of 0.500 M AgNO3 is added to 6.25 mL of 0.300 M NH4Cl, how many grams of AgCl are formed?
irina1246 [14]

Answer:

The answer to your question is 0.269 grams of AgCl

Explanation:

Data

[AgNO₃] = 0.50 M

Vol AgNO₃ = 7.80 ml

[NH₄Cl] = 0.30 M

Vol NH₄Cl = 6.25 ml

mass of AgCL

Balanced reaction

                 AgNO₃(aq)  +  NH₄Cl(aq)   ⇒   AgCl (s) + NH₄NO₃ (aq)

Process

1.- Calculate the moles of AgNO₃

Molarity = moles / volume

moles = Molarity x volume

moles = 0.50 x 0.0078

moles = 0.0039

2.- Calculate the moles of NH₄Cl

moles = 0.30 x 0.0063

moles = 0.00188

3.- Calculate the limiting reactant

The proportion of     AgNO₃(aq)  to  NH₄Cl(aq) is 1 :1, then, we conclude that the limiting reactant is NH₄Cl(aq), because there are less amount of this reactant in the experiment.

4.- Calculate the moles of AgCl

                     1 mol of NH₄Cl  ---------------- 1 mol of AgCl

              0.00188 mol of NH₄Cl ------------- x

                     x = (0.00188 x 1) /1

                     x = 0.00188 moles of AgCl

5.- Calculate the grams of AgCl

molecular mass of AgCl = 108 + 35.5 = 143.5 g

                         143.5 grams of AgCl -------------- 1 mol

                         x -------------------------------------------0.00188 moles of AgCl

                          x = (0.00188 x 143.5) / 1

                          x = 0.269 grams of AgCl

8 0
3 years ago
What is the [H+] and [OH-] of a 3.5 M HCIO3 solution?
levacccp [35]

Answer: H+ ia helyuim

explinanation: Hope this helped!!

3 0
2 years ago
NaCl and HCl both have chlorine but are different types of bonds.
Tema [17]

Answer:

In HCl ,bond between hydrogen and chlorine is covalent. But due to difference in electronegativity of hydrogen and chlorine,shared electron pair gets attracted towards chlorine. Due to this polar covalent

3 0
3 years ago
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