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Sloan [31]
3 years ago
14

Malik analyzed three samples to test which element was a metalloid. The table shows his results. A 7-column table with 3 rows. T

he first column titled element has entries A, B, C. The second column titled lustrous has entries yes, no, yes. The third column titled brittle has entries no, yes, yes. The fourth column titled how it reacts has entries base, acid, acid or base. The fifth column titled boiling point (degrees C) has entries not observed, negative 34.04, not observed. The sixth column titled melting point (degrees C) has entries 97.72, not observed, 1413.85. The seventh column titled electrical conductivity has entries high, very low, medium. Which element (A, B, or C) is most likely a metalloid?
Chemistry
2 answers:
Maru [420]3 years ago
6 0

Answer:C is most likely a metalloid

Explanation:A is a metal while B is a non metal. This is because when we look at the properties of metals, they are very lustrous and have a high conductivity. On the other hand, non metals are the opposite but metalloids have properties the are inbetween ie, they react with either an acid or base, and have a medium electrical conductivity unlike metals(high) anc non metals(low).

nikdorinn [45]3 years ago
3 0

Answer:

CCCCCCCCCCCCCC

Explanation:

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The pressure of a cloud varies with depth because of volume.
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3 years ago
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq) , as described b
Nostrana [21]

Answer:

0.676 grams of manganese (IV) oxide should be added.

Explanation:

Moles of chlorine gas = n

Volume of the chlorine gas = V = 205 mL = 0.205 L

Pressure of the chlorine gas = 705 Torr = \frac{705}{760}atm=0.928 atm

1 atm = 760 Torr

Temperature of the chlorine gas = T = 25°C = 25 + 273 K = 298 K

PV=nRT ( ideal gs equation)

n=\frac{PV}{RT}=\frac{0.928 atm\times 0.205 L}{0.0821 atm L/mol K\times 298 K}=0.00777 mol

MnO_2(s)+4HCl(aq)\rightarrow MnCl_2(aq)+2H_2O(l)+Cl_2(g)

According to reaction, 1 mole of chlorine gas is obtained from  1 mole of manganese(IV) oxide,then 0.00777 moles of chlorine gas will be obtained from :

\frac{1}{1}\times 0.00777 mol=0.00777 mol of manganese (IV) oxide

Mass of 0.00777 moles of manganese (IV) oxide:

0.00777 mol × 87 g/mol = 0.676 g

0.676 grams of manganese (IV) oxide should be added.

3 0
3 years ago
A green laser pointer emits light with a wavelength of 536 nm. What is the frequency of this light?
anastassius [24]

Answer:

Your answer is 5.63 × 10^14 Hz

We know the value of the speed of light and we are given the wavelength. All we have to do is rearrange the equation to solve for the frequency:

frequency: v = c/ λ

Now just plug in the given values:

v = 3.00 × 10 ^ 8 / 530 × 10^-9

v = 5.66 × 10 ^ 14 Hz

I hope this helps you.

3 0
3 years ago
Apply the given electronegativities to each bond in the examples below to see which are polar and which are nonpolar. Multiple b
Nesterboy [21]

Answer:

H-O-H  polar

O-C-O nonpolar

H-C-N   polar

Explanation:

Looking up the electronegativities of the atoms involved in this question, we have:

Atom   Electronegativity

H               2.2

C               2.55

N               3.04

O               3.44

All of the atoms differ in electronegativity resulting in individual dipole moments in H-O, O-C, H-C and C-N bonds. To find if the molecules will be polar we need to consider the structure of the compound to see if there is a resultant dipole moment.

In H-O-H, we have 2 lone pairs of electrons around the central oxygen atom which push the angle H-O-H  of the ideal tetrahedral structure to be smaller than 109.5 º  resulting in an overall dipole moment making it polar.

In O-C-O, we have two dipole moments that exactly cancel each other in the linear molecule  since the central carbon atom does not have lone pairs of electrons since it  has 2 double bonds. Therefore the molecule is nonpolar.

In H-C-N, again we have have a central carbon atom without lone pairs of electrons and the shape of the molecule is linear. But, now we have that the dipole moment in C-N is stronger than the H-C dipole because of the difference in electronegativity of nitrogen compared to hydrogen. The molecule has an overall dipole moment and it is polar.

8 0
3 years ago
Read 2 more answers
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