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Sloan [31]
3 years ago
14

Malik analyzed three samples to test which element was a metalloid. The table shows his results. A 7-column table with 3 rows. T

he first column titled element has entries A, B, C. The second column titled lustrous has entries yes, no, yes. The third column titled brittle has entries no, yes, yes. The fourth column titled how it reacts has entries base, acid, acid or base. The fifth column titled boiling point (degrees C) has entries not observed, negative 34.04, not observed. The sixth column titled melting point (degrees C) has entries 97.72, not observed, 1413.85. The seventh column titled electrical conductivity has entries high, very low, medium. Which element (A, B, or C) is most likely a metalloid?
Chemistry
2 answers:
Maru [420]3 years ago
6 0

Answer:C is most likely a metalloid

Explanation:A is a metal while B is a non metal. This is because when we look at the properties of metals, they are very lustrous and have a high conductivity. On the other hand, non metals are the opposite but metalloids have properties the are inbetween ie, they react with either an acid or base, and have a medium electrical conductivity unlike metals(high) anc non metals(low).

nikdorinn [45]3 years ago
3 0

Answer:

CCCCCCCCCCCCCC

Explanation:

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What is the element name for 2,2​
Strike441 [17]

Answer:

Helium

Explanation:

6 0
3 years ago
Read 2 more answers
For 2,663 kg of a compound with the formula Al(SO), determine the following quantities (4 pts each); a) The number of moles of t
Nastasia [14]

Answer:

a) 35.485 moles of Al(SO)

b) 35.485 moles of S atoms

c) 2.136197(10^{25}) Al atoms

d) 567.723 g of O

Explanation:

Let's define the following terms :

1 mol = 6.02.(10^{23}) elemental units

For example :

1 mol of oxygen atoms = 6.02.(10^{23}) oxygen atoms

Now, our compound has the following formula

Al(SO)

Where Al is aluminium

S is sulfur

And O is oxygen

All the subscripts are 1 so we can say the following :

1 molecule of Al(SO) has 1 atom of Al , 1 atom of S and 1 atom of O

In terms of moles :

1 mol of Al(SO) has 1 mol of Al , 1 mol of S and 1 mol of O

The molar masses of Al, S and O are

molarmass_{(Al)}=26.982\frac{g}{mol}

molarmass_{(S)}=32.065 \frac{g}{mol}

molarmass_{(O)}=15.999\frac{g}{mol}

If we sum all the molar masses =(26.982+32.065+15.999)\frac{g}{mol}=75.046\frac{g}{mol}

Finally, 75.046 g of Al(S0) is 1 mol of Al(SO) which contains 26.982 g of Al, 32.065 g of S and 15.999 g of O.

1 mol of Al(SO) contains 1 mol of Al, 1 mol of S and 1 mol of O.

Now we can calculate a),b),c) and d)

For a)

2.663 kg=2663g

75.046 g of Al(SO) = 1 mol of Al(SO)

2663 g of Al(SO) = x

x=\frac{2663}{75.046}mol=35.485 mol

2.663 kg of Al(SO) contains 35.485 moles of Al(SO)

b) and c) 1 mol of Al(SO) molecules contains 1 mol of S atoms and 1 mol of Al atoms

We have 35.485 moles of Al(SO) molecules so

We have 35.485 moles of S atoms

And 35.485 moles of Al atoms

If 1 mol = 6.02(10^{23})

35.485 moles of Al have (35.485)(6.02)(10^{23})=2.136197(10^{25}) Al atoms

d) 75.046 g of Al(SO) contains 15.999 g of O

2663 g of Al(SO) contains x g of O

x=\frac{(2663).(15.999)}{75.046} g

x = 567.723 g of O

6 0
3 years ago
Which sample contains more atoms: 3.89 g of nickel or 6.61 g of silver? defend your answer
Lubov Fominskaja [6]

Nickel contains more atoms.

<u>Explanation:</u>

Number of atoms is determined by the Avogadro number.

1 mole of substance contains 6.022 X 10²³ atoms.

Given:

Mass of Nickel, Ni = 3.89g

Molecular weight of Ni = 58.6934g

Number of moles of Ni = 3.89/58.6934g

Number of atoms of Ni = \frac{3.89 X 6.022 X 10^2^3}{58.6934}

Number of atoms of Ni = 0.39 X 10²³

Mass of silver, Ag = 6.61g

Molecular weight of Ag = 107.8682g

Number of moles of Ag = 6.61/107.8682

Number of atoms of Ag = \frac{6.61 X 6.022 X 10^2^3}{107.8682}

Number of atoms of Ag = 0.36 X 10²³

Therefore, Nickel contains for atoms.

4 0
3 years ago
The rocks and minerals of the Earth consist of compounds.
vesna_86 [32]

The correct answer its:

Inorganic

Hope it helps

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7 0
3 years ago
Read 2 more answers
Anita was using steel to make rusted sculptures. After building each sculpture, she caused the steel in the sculpture to rust by
alexandr1967 [171]

Answer:

The type of liquid in the tub (salt water or vinegar)

Explanation:

<em>The manipulated independent variable in Anita's experiment is </em><em>the type of liquid in the tub. </em>

The independent variable is the controlled or manipulated variable in the course of an experiment. It can also be referred to as the 'cause' variable which has the capacity to produce 'effects' on another variable - the dependent variable.

In this case, the type of liquid the tub is filled (salt water or vinegar) will hypothetically affect the rusting period of the steel. Hence, the dependent variable is the type of liquid the tub is filled while the dependent variable would be the time it takes for the steel to get rusted.

5 0
3 years ago
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