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Svet_ta [14]
3 years ago
13

A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 0.200 fg (where a femtogra

m, fg, is 10^−15g) and is swimming at a velocity of v = 1.00 μm/s , with an uncertainty in the velocity of 5.00 % . E. coli bacterial cells are around 1 μm (10^−6 m) in length. The student is supposed to observe the bacterium and make a drawing. However, the student, having just learned about the Heisenberg uncertainty principle, complains that she cannot make the drawing. She claims that the uncertainty of the bacterium's position is greater than the microscope's viewing field, and the bacterium is thus impossible to locate.
1. What is the uncertainty of the position of the bacterium?
Physics
1 answer:
andriy [413]3 years ago
3 0

Answer:

58.22pm

Explanation:

Look up attached file

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If an object weighs 300 N on earth, what is it’s mass on the moon?
inna [77]

Answer:

The mass of the object on the Moon (and anywhere else) is about 30.61kg. Please see more detail below.

Explanation:

Weight is the gravitational force exerted on the object and is a function of mass and gravitational acceleration:

(weight) = (mass) x (gravitational acceleration)

We are to find the mass, knowing the weight on Earth to be 300N:

(mass) = (weight on Earth) / (gravitational acceleration on Earth) = 300N / 9.8 m/s^2 = 30.61 kg

The mass of the object is 30.61kg.

The mass of the object is independent of gravity. Therefore the answer to the question "What is its mass on the Moon" is 30.61kg.

If the question were what is its weight on the Moon, the answer would be

(weight on Moon) = (mass) x (grav.accel. on Moon) = 30.61kg x 1.62 m/s^2 = 49.59N

which is about 1/6 of the object's weight on the Earth.

4 0
3 years ago
n astronaut who weighs 800 N on the surface of the earth lifts off from planet Zuton in a space ship. The free-fall acceleration
ANTONII [103]

Answer: 0.29 kN

Explanation:

We have the following data:

W_{E}=800 N is the weight of the astronaut on Earth

g_{E}=9.8 m/s^{2} is the free fall acceleration due gravity on Earth (directed downwards)

g_{Z}=3 m/s^{2} is the free fall acceleration due gravity on Zuton (directed downwards)

a=0.5 m/s^{2} is the acceleration of the spaceship at litoff (directed upwards)

We have to find the <u>magnitude of the force</u> F the space ship exerts on the astronaut.

Firstly, we have to know weight has a direct relation with the mass and the acceleration due gravity. In the case of Earth is:

W_{E}=mg_{E} (1)

Where m is the mass of the atronaut.

Isolating m:

m=\frac{W_{E}}{g_{E}} (2)

m=\frac{800 N}{9.8 m/s^{2}} (3)

m=81.63 kg (4)

Now that we know the mass of the astronaut, we can find its weight on Zuton:

W_{Z}=mg_{Z} (5)

W_{Z}=(81.63 kg)(3 m/s^{2}) (6)

W_{Z}=244.89 N (7)

Then, we can calculate the force the space ship exerts on the astronaut by the following equation:

F-W_{Z}=m.a (8)

Isolating F:

F=m.a+W_{Z} (9)

F=(81.63 kg)(0.5 m/s^{2})+244.89 N (10)

F=285.7 N \frac{1 kN}{1000 N}=0.285 kN (11)

Finally:

F=0.285 kN \approx 0.29 kN

5 0
4 years ago
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