Explanation:
Given
initial velocity(v_0)=1.72 m/s

using 
Where v=final velocity (Here v=0)
u=initial velocity(1.72 m/s)
a=acceleration 
s=distance traveled

s=0.214 m
(b)time taken to travel 0.214 m
v=u+at


t=0.249 s
(c)Speed of the block at bottom

Here u=0 as it started coming downward

v=1.72 m/s
<span>Usually alto-cumulus and alto-stratus are clouds that have been slowly lifted by the very slack slope of a warm front. The normal progression of this type of weather is to see the ceiling to go down, drizzle to happen, the wind to increase and dark nimbostratus and cumulonimbus full of rain or snow.
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The answer would be (D.) uranus
<u>Given data:</u>
wave length (λ) = 22 cm = 0.22 m,
speed of wave length(v) = 4 m/s ,
determine the frequency (f) = ?
We know that ,
wave length and frequency of light are closely related. The higher the frequency, shorter is the wavelength and vice-versa.
Mathematically, <em> λ = v/f -------------------- (i)</em>
<em> </em> where, λ = wave length (m)
v = speed of wave length (m/s)
f = frequency (Hz)
From the equation<em> </em><em>(i) </em>,<em> </em>
<em> </em><em>frequency (f) = v/λ</em>
= 4 / 0.22
= 18.18 /second
frequency (f) of the wave is 18 /sec or (18 Hz)
<em>Note:</em> frequency is defined as "<em>number of occurrences per unit time",</em> measured in<em> Hz</em>.
An integrated circuit is a b) thin slice of silicon with many solid-state components