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telo118 [61]
3 years ago
10

Which of the following are phase changes? Select all that apply.

Chemistry
2 answers:
lidiya [134]3 years ago
5 0

Answer: Options A, B, C, and D are all representing phase changes.

Explanation:

Phase change means change in the state of a substance from one form to another that is change of a liquid into solid, liquid into gas and vice versa.

In liquid freezing, the liquid is changing into solid so here phase is changing.

In solid melting, solid is changing into liquid so here phase is changing.

In ice melting, solid is changing into liquid so here phase is changing.

In sublimation of a solid, the solid changes to gas without changing into liquid. So, here also phase is changing.

When paper is burning, it is a chemical change as a new substance is formed which cannot be reversed into paper again.

Therefore, options A, B, C, and D are all representing phase changes.


kogti [31]3 years ago
4 0
A, B, C, and D, because they are changing from a solid to a liquid, liquid to solid, and solid to gas. Phase changes are when a solid, liquid, or gas, turns into a solid, liquid, or gas. Ex. Ice melting is a solid changing into a liquid. Hope this helps!
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Cathodic protection of iron involves using another more reactive metal as a sacrificial anode. Classify each of the following me
Anika [276]

Answer:

a. Ag ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

b. Mg ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

c. Cu ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

d. Pb ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

e. Sn ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

f. Zn ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

g. Au ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

Explanation:

Cathodic protection of iron involves using another more reactive metal as a sacrificial anode. The reactivity series of metals arranges metals based on decreasing order of reactivity. The more reactive metals are found higher up in the series while the least reactive metals are found at the lower ends of the series. Thus, metals above iron in the reactivity series can serve as sacrificial anodes by protecting against corrosion, while those lower than iron cannot.

Based on the reactivity series, the following metals can be classified as either a sacrificial anode for iron or not:

a. Ag ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

b. Mg ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

c. Cu ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

d. Pb ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

e. Sn ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

f. Zn ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

g. Au ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

6 0
3 years ago
How many molecules are in 1.75 moles of Caco3?
saw5 [17]

Answer:

1.054 x 10²⁴ molecules

Explanation:

In order to convert moles <em>of any given substance</em> into a number of molecules, we need to use <em>Avogadro's number</em>, which states the number of molecules -or atoms, in the case of elements- present in one mol:

  • In one mol there are 6.023x10²³ molecules.

We now <u>convert 1.75 moles into molecules</u>:

  • 1.75 mol * 6.023x10²³ molecules/mol = 1.05x10²⁴ molecules
5 0
3 years ago
How are mass and volumes alike?
AlladinOne [14]
Kind of this is probably wrong Mass weight of solid, volume weight of liquid?
3 0
4 years ago
How many independent variables can you have in an experiment for it to be valid?
Lemur [1.5K]

Answer:

There are often not more than one or two independent variables tested in an experiment.

3 0
3 years ago
The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the
VLD [36.1K]
The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2 
so 1mole of NH3 will give 1 mole of NO2 
43.9 grams of NH3 contains 2.58 moles 
so 2.58 moles will be produced of NO2 
which is 118.7 grams this the amount of oxygen that is used.
8 0
3 years ago
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