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3 years ago

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Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 15 grams and velocity of 3 centimeters per s

econd has a kinetic energy of 27 ergs. Find the kinetic energy for a mass of 5 grams and velocity of 9 centimeters per second.

1 answer:

ratelena [41]3 years ago

6 0

Answer:

Explanation:

Given

Kinetic energy varies jointly as mass and square of velocity

$K.E.\propto m$

$K.E.\propto v^2$

$K.E.=kmv^2$

for $m=15 gm\ and\ v=3 cm/s$

$K.E.=27 ergs$

$27=k(15)(3)^2 -----1$

for $m=5 gm, v=9 cm/s$

$K.E.=k(5)(9)^2----2$

Divide 1 & 2 we get

$\frac{27}{K.E.}=\frac{15\times 3^2}{5\times 9^2}$

$K.E.=81 ergs$

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Explanation:

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$N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}$

Where:

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$d_{a}$ : is the distance in air = 1.50 cm - 0.225 cm = 1.275 cm

$\lambda_{g}$ : is the wavelength in glass

$\lambda_{a}$ : is the wavelength in air = 620 nm

To find the wavelength in glass we need to use the following equation:

$n_{g}*\lambda_{g} = n_{a}*\lambda_{a}$

Where:

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$n_{a}$ : is the refraction index of air = 1

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Hence, the number of wavelengths is:

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$N = \frac{2.25 \cdot 10^{-3} m}{344.4 \cdot 10^{-9} m} + \frac{1.275 \cdot 10^{-2} m}{620 \cdot 10^{-9} m}$

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Complete Question

The complete question is shown on the first uploaded image

Answer:

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