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Paha777 [63]
3 years ago
8

Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 15 grams and velocity of 3 centimeters per s

econd has a kinetic energy of 27 ergs. Find the kinetic energy for a mass of 5 grams and velocity of 9 centimeters per second.
Physics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

Explanation:

Given

Kinetic energy varies jointly as mass and square of velocity

K.E.\propto m

K.E.\propto v^2

K.E.=kmv^2

for m=15 gm\ and\ v=3 cm/s

K.E.=27 ergs

27=k(15)(3)^2 -----1

for m=5 gm, v=9 cm/s

K.E.=k(5)(9)^2----2

Divide 1 & 2 we get

\frac{27}{K.E.}=\frac{15\times 3^2}{5\times 9^2}

K.E.=81 ergs

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A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at
faust18 [17]

The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

<h3>What is the resultant force the two engines exert on the rocket?</h3>

The resultant force on the rocket is calculated thus:

The 513N thrust is resolved into vertical and horizontal components;

Horizontal component: 513N cos(32.4°) = 433.14 N

Vertical component: 513N sin(32.4°) = 274.88 N

Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N

Total force at right angles:

0 + 274.88 N = 274.88 N

The resultant force (F) is then given as follows:

F² = a² + b²

F² = (1158.14 N)² + (274.88 N)²

F = √1,416,847.27

F = 1,190.3

To find the direction:

tan X 274.88 N / 1,158.14 N

X = tan⁻¹ 0.237346089419241

X = 13.35°

Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.

Learn more about resultant force at: brainly.com/question/17434363

#SPJ1

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