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Paha777 [63]
3 years ago
8

Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 15 grams and velocity of 3 centimeters per s

econd has a kinetic energy of 27 ergs. Find the kinetic energy for a mass of 5 grams and velocity of 9 centimeters per second.
Physics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

Explanation:

Given

Kinetic energy varies jointly as mass and square of velocity

K.E.\propto m

K.E.\propto v^2

K.E.=kmv^2

for m=15 gm\ and\ v=3 cm/s

K.E.=27 ergs

27=k(15)(3)^2 -----1

for m=5 gm, v=9 cm/s

K.E.=k(5)(9)^2----2

Divide 1 & 2 we get

\frac{27}{K.E.}=\frac{15\times 3^2}{5\times 9^2}

K.E.=81 ergs

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Explanation:

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What happens to temperature during condensation?
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CONDENSATION is the process by which water vapor (gas) in the atmosphere turns into water (liquid state). It is the opposite of EVAPORATION.Cool temperatures are essential for condensation to happen, because as long as the temperature in the atmosphere is high, it can hold the water vapor and delay condensation. So the temperature in condensation rises.

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The total blood volume of a human is 75 ml/kg. If the volumetric flow rate is the same in adults and children, how much more blo
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The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

<h3>What is flow rate?:</h3>

This is the volume of fluid flowing in a vessel per unit time.

First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.

Using,

  • V = F'm................ Equation 1

Where:

  • V = Volume of the blood
  • F' = Flow rate
  • m = mass of blood.

For the Adult,

Given:

  • m = 70 kg
  • F = 75 ml/kg

Substitute these values into equation 1

  • V = 70(75)
  • V = 5250 ml.

For the child,

Given:

  • m = 20 kg
  • F = 75 ml/kg

Substitute these values into equation 1 also

  • V = 75(20)
  • V = 1500 ml.

The amount of blood that flows more through the adult than the child is

  • A = 5250-1500
  • A = 3750 ml.

Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

Learn more about flow rate here: brainly.com/question/21630019

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A 6.2 kg cannonball is fires from a 280 kg cannon. The cannon recoils with a velocity of 4.9 m/s. What is the velocity of the ca
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3 years ago
A 2.45-kg frictionless block is attached to an ideal spring with force constant 355 N/m. Initially the spring is neither stretch
ANTONII [103]

Answer:

A.    A = 0.913 m

B.    amax = 132.24m/s^2

C.    Fmax = 324.01N

Explanation:

When the block is moving at the equilibrium point , its velocity is maximum.

A. To find the amplitude of the motion you use the following formula for the maximum velocity:

v_{max}=A\omega          (1)

vmax = maximum velocity = 11.0 m/s

A: amplitude of the motion = ?

w: angular frequency = ?

Then, you have to calculate the angular frequency of the motion, by using the following formula:

\omega=\sqrt{\frac{k}{m}}           (2)

k: spring constant = 355 N/m

m: mass of the object = 2.54 kg

\omega = \sqrt{\frac{355N/m}{2.45kg}}=12.03\frac{rad}{s}

Next, you solve the equation (1) for A and replace the values of vmax and w:

A=\frac{v}{\omega}=\frac{11.0m/s}{12.03rad/s}=0.913m

The amplitude of the motion is 0.913m

B. The maximum acceleration of the block is given by:

a_{max}=A\omega^2 = (0.913m)(12.03rad/s)^2=132.24\frac{m}{s^2}

The maximum acceleration is 132.24 m/s^2

C. The maximum force is calculated by using the second Newton law and the maximum acceleration:

F_{max}=ma_{max}=(2.45kg)(132.24m/s^2)=324.01N

It is also possible to calculate the maximum force by using:

Fmax = k*A = (355N/m)(0.913m) = 324.01N

The maximum force exertedbu the spring on the object is 324.01 N

4 0
3 years ago
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