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Sophie [7]
3 years ago
13

Classical physics is a good approximation to modern physics under certain circumstances. What are they?

Physics
1 answer:
Aleks [24]3 years ago
4 0

Answer and Explanation:

In classical physics we study about macroscopic objects and in modern physics we study about microscopic objects but under some circumstances classical physics is a approximation to modern physics such as

  • The object must be microscopic but they should be large enough so that we can see that through a microscope
  • The speed of the object should be very less it should be about 1 % of the speed of the light
  • They should be involved with very week gravitational field

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Confusing, fill the venn diagram?
Irina18 [472]

Answer:

electromagnetic waves= LIGHT, TRAVELS IN A VACUUM, VIBRATIONS IN MAGNETIC FIELD

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both= TRANSFERS ENERGY, AMPLITUDE, FREQUENCY, WAVELENGTH,

Explanation:

electromagnetic waves don't need particles/atoms to travel through whilst matter/mechanical waves do.

4 0
3 years ago
When the man inside the treadmill steps up, what force pulls home back? In what direction does this force move him?
poizon [28]
These image should help you out

4 0
3 years ago
Which is not an assumption about particles in a gas according to the kinetic theory?
bearhunter [10]
Let us evaluate the given assumptions according to the kinetic theory for an ideal gas.

a.
The motion of one particle is unaffected by other particles unless the particles collide.
TRUE. The particles are in random motion unless they collide.

b.
The forces of attraction among particles keep the particles close together.
FALSE. No forces act between particles except during collision.

c.
Under ordinary conditions, forces of attraction between particles can be ignored.
TRUE. 

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4 0
3 years ago
. The penalties for a person's second DUI conviction include completion of __________ hours of DUI school.
Ghella [55]

Answer:

21

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3 0
2 years ago
A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
maksim [4K]

Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

  The first amplitude of the wave is  E_{max}1 =  98.02 \  V/m

  The first  depth  is  D_1 =  10 \  m

   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

   The second depth is D_2 = 100 \ m

Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

=>   \alpha  =  \frac{0.18}{90}

=>    \alpha =  0.002 Np/m

       

4 0
3 years ago
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