1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sophie [7]
3 years ago
13

Classical physics is a good approximation to modern physics under certain circumstances. What are they?

Physics
1 answer:
Aleks [24]3 years ago
4 0

Answer and Explanation:

In classical physics we study about macroscopic objects and in modern physics we study about microscopic objects but under some circumstances classical physics is a approximation to modern physics such as

  • The object must be microscopic but they should be large enough so that we can see that through a microscope
  • The speed of the object should be very less it should be about 1 % of the speed of the light
  • They should be involved with very week gravitational field

You might be interested in
A solid metal ball of radius 1.5 cm bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing a
blsea [12.9K]

We have that the electric field at the center of the metal ball due only to the charges on the surface of the metal ball is

E=7*10^{9}N/C

From the question we are told that

A solid metal ball of radius 1.5 cm

bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing

uniformly distributed charge of -7 nC

The distance between the centers of the balls is 9 cm

Generally the equation for the electric field  is mathematically given as

E=\frac{kq_2}{d^2}\\\\E=\frac{(9*10^9)7*10^{-2}}{9*10^{-2}}\\\\

E=7*10^{9}N/C

For more information on this visit

brainly.com/question/21811998

4 0
3 years ago
Ms. Garcia’s car can go from rest to 25 m/s in 10 seconds. The car’s velocity changes at a uniform rate. How far does the car tr
vampirchik [111]

We will use this equation:

s = 1/2*a*t^2 + v0*t + s0

where:

s = space traveled

a = acceleration

t = time

v0 = initial speed

s0 = initial space

In this case::

v0 = 0

s0 = 0

So our equation will look like that now:

s = 1/2 * a * t^2

let's calculate the acceleration first of all:

a = (vf - vi) / t

where vf is the final speed and vi is the initial speed. t is the time.

a = (25m/s) / 10s = 2.5 m/s^2

Now we can calculate the space:

s = 1/2 * (2.5 m/s^2) * (10s)^2 = 125m

---

Hope it was helpful! Have a great day.

4 0
3 years ago
A circuit contains two 2,000 resistors connected in parallel. What is the total resistance of the circuit?
GenaCL600 [577]
RT = R1 R2/ R1 + R2

R1 = R2 = 2k ohm

RT = R/2 = 2k/2 = 1k ohm 
5 0
3 years ago
The Hubble Space Telescope in orbit above the Earth has a 2.4 m circular aperture. The telescope has equipment for detecting ult
strojnjashka [21]

Answer:

Option d

The minimum angular separation between two objects that the Hubble Space Telescope can resolve is 4.8x10^{-8}rad.  

Explanation:

The resulting image in a telescope that will be gotten from an object is a diffraction pattern instead of a perfect point (point spread function (PSF)).

That diffraction pattern is gotten because the light encounters different obstacles on its path inside the telescope (interacts with the walls and edges of the instrument).

 

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.    

 

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction pattern maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in analytical way by means of the Rayleigh criterion.          

\theta = 1.22\frac{\lambda}{D}  (1)

Where \lambda is the wavelength and D is the diameter of the telescope.

Notice that it is necessary to express the wavelength in the same units than the diameter.

\lambda = 95nm \cdot \frac{1x10^{-9}m}{1nm} ⇒ 9.5x10^{-8}m

Finally, equation 1 can be used.

\theta = 1.22(\frac{9.5x10^{-8}m}{2.4m})

\theta = 4.8x10^{-8}rad              

Hence, the minimum angular separation between two objects that the Hubble Space Telescope can resolve is 4.8x10^{-8}rad.    

5 0
3 years ago
A bar of gold has a temperature of 31°C, and a bar of aluminum has a
Katarina [22]
Different dense matters
3 0
3 years ago
Other questions:
  • The diagram shows a vertical number line. what is the position of point X?
    6·2 answers
  • the idea that god created the first governments and selected those of royal birth to rule is referred to as_____.
    6·2 answers
  • Scientists find the same type of index fossil in two different locations on Earth. What can they conclude from this discovery?
    11·2 answers
  • Avogadro’s law and charles’s law describe a proportionality of the volume of a gas when the pressure is constant. Describe the p
    5·1 answer
  • Spot the dog is running after a ball.In 22m,he accelerates at a constant rate,and his velocity increases from 5.0m/s to 11m/s. W
    9·1 answer
  • The diagram below represents an electromagnetic wave. Please Help<br>​
    10·1 answer
  • The name of the Sl unit for force is the ___?<br><br> A. Joule<br> B. Newton<br> C.Watt
    13·2 answers
  • 17. Calculate the amount of gravitational potential energy at the top of one 4 points hill. The mass of the coaster is 500 kg. T
    7·1 answer
  • See the diagram above. Which of the following is the best prediction of what would happen if you increased the distance in secti
    8·1 answer
  • Calculate the lowest energy (in ev) for an electron in an infinite well having a width of 0.050 mm.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!