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Leya [2.2K]
3 years ago
15

Cobalt III hydroxide and nitric acid react according to the following balanced equation:

Chemistry
1 answer:
velikii [3]3 years ago
5 0
Q1)
molarity is defined as the number of moles in a volume of 1 L.
the molarity of the solution to be prepared is 0.42 M
The volume of the solution to be prepared is 5.2 L
the number of moles of Co(OH)₃ in 1 L solution - 0.42 mol
therefore number of moles required in 5.2 L - 0.42 mol/L x 5.2 L = 2.184 mol
molar mass of Co(OH)₃ - 110 g/mol
mass of Co(OH)₃ required to prepare the solution - 2.184 mol x 110 g/mol = 240.2 g
mass of Co(OH)₃ required - 240.2 g

Q2)
the balanced equation for the reaction between Co(OH)₃ and HNO₃ is;
Co(OH)₃ + 3HNO₃ --> Co(NO₃)₃ + 3H₂O
stoichiometry of Co(OH)₃ to HNO₃ is 1:3
the number of Co(OH)₃ moles present - 2.184 mol
the number of HNO₃ moles required - 2.184 x 3 = 6.552 mol
molarity of HNO₃ is 1.6 M
If 1.6 mol is in 1 L of solution 
then volume containing 6.552 mol is - 6.552 mol / 1.6 mol/L = 4.095 L
therefore volume of HNO₃required is 4095 mL 

Q3)
the balanced equation
Co(OH)₃ + 3HNO₃ --> Co(NO₃)₃ + 3H₂O
stoichiometry of Co(OH)₃ to H₂O is 1:3
the number of Co(OH)₃ moles reacted - 2.184 mol 
when 1 mol of Co(OH)₃ reacts - 3 mol of H₂O is formed
therefore when 2.184 mol of Co(OH)₃ moles react - 2.184 x 3 = 6.552 mol of H₂O formed
therefore number of H₂O moles formed - 6.552 mol
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have a good day

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