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3 years ago

Which statement below is true?

Chemistry

1 answer:

kykrilka [37]3 years ago

7 0

Answer:

a) At a given temperature, C₂H₆ has a higher vapor pressure than C₄H₁₀.

Explanation:

Which statement below is true?

a) At a given temperature, C₂H₆ has a higher vapor pressure than C₄H₁₀. TRUE. C₂H₆ has a lower molar mass than C₄H₁₀ and a higher vapor pressure at most temperatures.

b) The strongest intermolecular attractive forces present in liquid CCl₄ are dipole-dipole forces. FALSE. CCl₄ is nonpolar, so the strongest intermolecular forces are dispersion forces.

c) HCl has a higher boiling point than LiCl. FALSE. LiCl (ionic compound) has a higher boiling point than HCl (covalent compound).

d) H₂O has a greater polarizability than H₂Se. FALSE. Se has a larger atomic radius than O which is why H₂Se has a greater polarizability than H₂O.

e) In general, the stronger the intermolecular attractive forces, the lower the ∆Hºvap. FALSE. In general, the stronger the intermolecular attractive forces, the higher the ∆Hºvap.

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Why do we use only a very small flame to heat the Thiele tube when determining the melting point of a crystalline solid?

Strike441 [17]

The Thiele tube which is look like a triangle, used for the determination of melting and boiling point of the solid and liquid sample respectively. The tube consists of high viscous oil. The mouth of the triangle tube consists the thermometer and the sample through a rubber stopper. The tube is always heated in low flame as the heating mechanism of the oil is through convection current process, in which the molecules of the oil heated passes through out the bulk to make a uniform heat of the liquid. The uniform heat of the liquid is necessary to determine the exact melting point of the solid. Also the low heating rate is compulsory so that the rate of convection current be slow. The high heating rate may cause fast convection in the oil and the hot oil can spill out from the tube and may cause an accident.

4 0

3 years ago

How many moles of gas would you have if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature

seraphim [82]

Answer: There are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

Explanation:

Given: Volume = 38.0 L

Pressure = 1430 mm Hg (1 mm Hg = 0.00131579 atm) = 1.9 atm

Temperature = 273.15 K

Using ideal gas equation, the moles of gas will be calculated as follows.

$PV = nRT\\$

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T =temperature

Substitute the values into above formula as follows.

$PV = nRT\\1.9 atm \times 38.0 L = n \times 0.0821 L atm/mol K \times 273.15 K\\n = \frac{1.9 atm \times 38.0 L}{0.0821 L atm/mol K \times 273.15 K}\\= 3.2 mol$

Thus, we can conclude that there are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

5 0

3 years ago

When particles collide, they transfer .

AnnZ [28]

When particles collide, they transfer fro their thermal energy.

Hope this helps.
______________________
To sum that up it’s -Energy-

3 0

3 years ago

Read 2 more answers

If you digested 25 mg of pure ferrocene in nitric acid and then diluted the resulting solution up to 500 mL with 1% aqueous hydr

Vilka [71]

Answer:

1.345*10⁻⁴ mol/L

15.023 mg/L

Explanation:

The chemical formula of ferrocene is Fe(C₅H₅)₂, thus its molecular weight is:

55.845 g/mol + 10*12g/mol + 10 *1g/mol = 185.845 g/mol

The moles of Fe contained in 25 mg (or 0.025 g) of ferrocene are:

$0.025gFerrocene*\frac{1molFerrocene}{185.845g} *\frac{1mol Fe}{1molFerrocene}=1.345*10^{-4} molFe$

The final volume is 500 mL, or 0.5 L. So the iron concentration in mol/L is:

$\frac{1.345*10^{-4}molFe}{0.5L}= 2.69*10^{-4} mol/L$

We can convert that value into mg/L:

$2.69*10^{-4} \frac{molFe}{L} *\frac{55.845g}{1molFe}*\frac{1000mg}{1g}=15.023 mg/L$

6 0

4 years ago

The half life of a certain radioactive element is 1,250 years what percent of the atoms remain after 7500 years

andrezito [222]

Each half-life results in ~50% (1/2) of the original element remaining.

7500/1250 = 6 half-lives, so 100(1/2)^6
= 100(0.015625)
= 1.5625% of the original element would remain

7 0

3 years ago

Read 2 more answers