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4 years ago

Where would you find an inclined plane in a fan

Physics

2 answers:

ivanzaharov [21]4 years ago

8 0

The blades that spin around in the fan, because they are flat and produce work

Licemer1 [7]4 years ago

6 0

I don't think there's none cause the blades would be wedges

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Which can associate a suspects gun with a crime

sergeinik [125]

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The Dinklegorb casings that are left behind at the scene of the crime

Explanation:

Every gun leaves behind DG

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3 years ago

High- and low-pressure areas leading to air movement happen when there are differences in:

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3 years ago

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4 A magnet can exert a force of attraction or a force of repulsion on another magnet.

GenaCL600 [577]

Answer:

Push -repulsion

Pull - attraction

Explanation:

When two magnets are brought together, a push happens when a force of repulsion is experienced where the magnets move away from each other. This means their polarity is the same and this will cause the magnet to push away from each other.

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3 years ago

The part of the shore that represents the water's edge and migrates back and forth with the tide is known as the ________.

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3 years ago

A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A se

igomit [66]

Answer:

$W_2=-12J$

Explanation:

The work of force 2 will be given by the vectorial equation $W_2=F_2.d$ . We know the value of $F_1$ and have information about its movement, which relates to the net force $F=F_1+F_2$ .

About this movement we can obtain the acceleration using the equation $v_f^2=v_i^2+2ad$ . Since it departs from rest we have $a=\frac{v_f^2}{2d}$ .

And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have $F_2=F-F_1=ma-F1=\frac{mv_f^2}{2d}-F_1$

And we had the work done by force 2 as:

$W_2=F_2.d=\frac{mv_f^2}{2}-F_1d$

(The sign will be given algebraically since we take positive the direction to the right.)

With our values:

$W_2=\frac{(10kg)(2m/s)^2}{2}-(8N)(4m)=-12J$

Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:

$W_1+W_2=K_f-K_i=K_f=\frac{mv_f^2}{2}$

Which leads us to the previous equation straightforwardly.

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3 years ago