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Pavel [41]
4 years ago
14

Give me the definition of quantum physics

Physics
2 answers:
spayn [35]4 years ago
4 0

Answer:

<em>Quantum</em><em> physics</em><em> </em><em>underlies</em><em> </em><em>how</em><em> </em><em>atoms</em><em> </em><em>work,</em><em> </em><em>and </em><em>so </em><em>why</em><em> </em><em>chemistry</em><em> </em><em>and</em><em> </em><em>biology</em><em> </em><em>work</em><em> </em><em>as</em><em> </em><em>they</em><em> </em><em>do</em><em>.</em>

Explanation:

Put it simply, it's the physics that explains how everything works: the best description we have of the nature of the particles that make matter and the forces with which they interact.

sorry if I'm wrong

liq [111]4 years ago
3 0

Answer:

Its the study of matter and energy on a more internal level.

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Therefore, <u>A: Position of an object</u> is the correct answer.

4 0
3 years ago
An instructor’s laser pointer produces a beam of light with a circular cross section of diameter 0.900 mm and a total power outp
il63 [147K]

Answer:

E_0 = 2180.53N/C.

B_0 = 7.27*10^{-6}T.

U_{avg} = 4.2*10^{-5}J/m^3.

Explanation:

The Intensity I of the beam is

I = P /A

The diameter of the beam is 0.900mm; therefore, the area is

A = \pi( \dfrac{0.900*10^{-3}}{2} )^2

A = 6.36*10^{-7}m^2

and since P = 4.00*10^{-3}W, the intensity of the beam is

I = \dfrac{4.00*10^{-3}W}{6.36*10^{-7}m^2}

\boxed{I = 6289.3W/m^2.}

Now, the intensity I is related to E_0 by the relation

I = \dfrac{E_0^2}{2\mu_0 c}

solving for E_0 we get

E_0 = \sqrt{2\mu_0 c I}

putting in the numbers we get:

E_0 = \sqrt{2(1.26*10^{-6}) (3*10^8) (6289.3)}

\boxed{E_0 = 2180.53N/C.}

The amplitude of magnetic field B_0 is related to E_0 by

B_0 = \dfrac{E_0}{c}

putting in numerical values we get:

B_0 = \dfrac{2180.53}{3*10^8}

\boxed{B_0 = 7.27*10^{-6}T. }

The average energy density of the laser light is

U_{avg} = \epsilon_0 E_0^2

U_{avg} = (8.85*10^{-12}) (2180.53)^2

\boxed{U_{avg} = 4.2*10^{-5}J/m^3.}

8 0
4 years ago
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Explanation:

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Answer:

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Explanation:

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Answer:

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