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Aleonysh [2.5K]
3 years ago
10

Which of Newton's laws introduces the concepts of action/reaction forces?

Chemistry
2 answers:
viktelen [127]3 years ago
7 0

It would be D.3

Hope I helped please give me brainliest answer


masha68 [24]3 years ago
4 0
It is number three for sure
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How to round the decimal 4.15 to the hundredths place?​
gladu [14]

Answer:4.15 is already in the hundreths place so you are good!

if it was 4.155 then you would round it to 4.16 but its NOT that so the answer IS 4.15

Explanation:

8 0
2 years ago
At equilibrium, ________. At equilibrium, ________. all chemical reactions have ceased the rate constants of the forward and rev
balandron [24]

Answer:

<em>At equilibrium, the rate of the forward, and the reverse reactions are equal.</em>

Explanation:

In an equilibrium chemical reaction, the rate of forward reaction, is equal to the rate of reverse reaction. Note that the reactions does not cease at equilibrium, but rather, the reactants are converted to product, at the same rate at which the product is also being converted into the reactants in the reaction. When chemical equilibrium is reached, a careful calculation of the value of equilibrium constant is approximately equal to 1.

NB: If the value of equilibrium constant is far far greater than 1, then the reaction will favors more of the forward reaction, and if far far less than 1, the reaction will favor more of the reverse reaction.

6 0
3 years ago
Ava threw a hamster at her sister the other day she used 12N of force to accelerate the hamster at 8m/s2.what was the mass of th
xenn [34]

<u>We are given:</u>

The force applied on the poor hamster (F) = 12 N

Acceleration of the poor Hamster (a) = 8 m/s²

<u>Solving for the mass of the Poor Hamster:</u>

From newton's second equation of motion, we know that:

F = ma

<em>replacing the given values</em>

12 = 8 * m

m = 12/8 kg

m = 3/2 kg

The poor Hamster weighs 3/2 kg

8 0
2 years ago
Consider the unbalanced equation for aluminum and oxygen producing aluminum oxide: Al + O₂ → Al₂O₃. Which of the following shows
DIA [1.3K]

Answer:

A answer is correct that help

6 0
3 years ago
How many moles of HCl are present in 0.70 L of a 0.33 M HCl solution? (molar mass of HCl = 36.46 g/mol)
Vilka [71]

Answer:-

0.231 moles

Explanation:-

From the question we are told that

Volume of HCl solution = 0.70 L

Strength of HCl solution = 0.33 M

Here M stands for molarity. Molarity is the number of moles of the substance present per Litre of solution. So in place of M we can write moles / L

Number of moles of HCl solution = Volume of HCl solution x Strength of HCl solution

= 0.70 L x 0.33 moles / L

= 0.231 moles.

0.231 moles of HCl are present in 0.70 L of a 0.33 M HCl solution

5 0
3 years ago
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