1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svetlana [45]
2 years ago
14

when a constant force acts upon an object the acceleration of the object varies inversely with its mass. when a certain constant

force acts ipon an objec twith mass 21khm the accerlation of the object is 3 m/2^2. If the same force acts upon another object whose mass is 9kg. What would this object's acceleration be?
Physics
1 answer:
solong [7]2 years ago
8 0

Explanation:

When a constant force acts upon an object the acceleration of the object varies inversely with its mass.

a\propto \dfrac{1}{m}

or

\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}

If m₁ = 21 kg, a₁ = 3 m/s², m₂ = 9 kg

We need to find a₂

So,

a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{21\times 3}{9}\\\\a_2=7\ m/s^2

So, if mass is 9 kg, its acceleration is 7 m/s².

You might be interested in
Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasonin
anygoal [31]

Answer:

ive answered this

Explanation:

please check your previose question

6 0
3 years ago
A solid of density 8000 kgm.. weighs 0.8 kgf in air. When it is completely
ad-work [718]

Answer:<em> 0.5kg</em>

Explanation:

5 0
2 years ago
I think I know the answer but I am not sure
Romashka [77]
The answer is a

Hope this helps!
5 0
3 years ago
Read 2 more answers
A runner traveling with an initial velocity of 1.1 m/s accelerates at a constant rate of 0.8 m/s2fora time of 2.0 s.(a).What is
pychu [463]

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

v = u + at

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.

7 0
2 years ago
A stretched string has a mass per unit length of 5.40 g/cm and a tension of 17.5 N. A sinusoidal wave on this string has an ampl
kondaur [170]

Answer:

Part a)

y_m = 0.157 mm

part b)

k = 101.8 rad/m

Part c)

\omega = 579.3 rad/s

Part d)

here since wave is moving in negative direction so the sign of \omega must be positive

Explanation:

As we know that the speed of wave in string is given by

v = \sqrt{\frac{T}{m/L}}

so we have

T = 17.5 N

m/L = 5.4 g/cm = 0.54 kg/m

now we have

v = \sqrt{\frac{17.5}{0.54}}

v = 5.69 m/s

now we have

Part a)

y_m = amplitude of wave

y_m = 0.157 mm

part b)

k = \frac{\omega}{v}

here we know that

\omega = 2\pi f

\omega = 2\pi(92.2) = 579.3 rad/s

so we  have

k = \frac{579.3}{5.69}

k = 101.8 rad/m

Part c)

\omega = 579.3 rad/s

Part d)

here since wave is moving in negative direction so the sign of \omega must be positive

4 0
3 years ago
Other questions:
  • Which side of continents have a colder climate than might be expected?
    9·2 answers
  • Two small insulating spheres with radius 9.00*10^-2m are separated by a large center-to-center distance of 0.520m . One sphere i
    13·1 answer
  • The study of the living and non living things in a environment is
    9·1 answer
  • What is the angular speed of a body vibrating<br>at 50 cycles per second:​
    11·1 answer
  • Gravitational Acceleration inside a Planet
    6·1 answer
  • A double-slit experiment is performed with light of wavelength 620 nm. The bright interference fringes are spaced 2.3 mm apart o
    5·1 answer
  • How do you find initial velocity?
    13·1 answer
  • All matter exists in three forms: solid, liquid, &amp; gas . Each form is called a ________________.
    15·2 answers
  • Help fast please physics
    7·1 answer
  • Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!