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hjlf
3 years ago
10

guys im morgz im going to put a nail on the seat in my mom room and im going to see how up her a- s s it will go lets see

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

go outside and ponder your life choices dork.

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How much energy must be added to a 1 kg piece of gold with a specific heat of 130 j/kg to increase its temperature from 20 c to
Lorico [155]

Q = 10.4 \; \text{kJ}

The specific heat of a material gives the energy it takes to increase the temperature of one unit mass of the material by one unit temperature. The SI unit for specific heat c is therefore \text{J} /\text{kg} \cdot \textdegree{\text{C}}.

The formula relating the energy required to raise the temperature of m grams of a substance with specific energy c by \Delta T degrees is

Q= c \cdot m \cdot \Delta T

The question provides the following information:

  • c = 130\; \text{J} /\text{kg} \cdot \textdegree{\text{C}} for gold
  • m= 1 \; \text{kg}
  • \Delta T = 100 \textdegree{\text{C}} - 20 \textdegree{\text{C}} = 80 \textdegree{\text{C}}

Apply the formula:

\begin{array}{ccc} Q & = & c \cdot m \cdot \Delta T\\  & = & 130 \; \text{J} \cdot \text{kg}^{-1} \cdot \textdegree{\text{C}}^{-1} \times 1 \; \text{kg} \times 80 \;  \textdegree{\text{C}}\\ & = & 1.04 \times 10^{4} \;\text{J}\\ & = & 10.4 \; \text {kJ} \end{array}

7 0
4 years ago
a student used 10 mL water instead of 30 mL for extraction of salt from mixture. How may this change the percentage of NaCl extr
Anit [1.1K]
It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.

If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:

360 g : 1 L = x g : 30 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 30 mL

Now, crossing the products:
x </span>· 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000 
x = 10.8 g

So, from 30 mL mixture, 10.8 g of NaCl could be extracted.

Let's calculate the same for 10 mL water instead of 30 mL.

360 g : 1 L = x g : 10 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 10 mL

Now, crossing the products:
x </span>· 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000 
<span>x = 3.6 g
</span>
<span>So, from 10 mL mixture, 3.6 g of NaCl could be extracted.
</span>
Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and <span>from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
</span>3.6/10.8 = 1/3

Therefore, i<span>t will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water. </span>
5 0
3 years ago
A container of carbon dioxide has a volume of 260 cm at a temperature of 22.0°C. If the
Oxana [17]

Answer:

V₂ =279.4 cm³

Explanation:

Given data:

Initial volume = 260 cm³

Initial temperature = 22.0°C

Final temperature = 44.0°C

Final volume = ?

Solution;

22.0°C (22+ 273 = 295k)

44.0°C(44+273 = 317k)

Formula:

According to Charles's law

V₁/T₁ = V₂/T₂

Now we will put the values in formula:

V₂ = V₁×T₂ / T₁

V₂ = 260 cm³ × 317k / 295k

V₂ = 82420 cm³. k  / 295k

V₂ =279.4 cm³

3 0
4 years ago
Consider the following representation of a reaction mechanism.
Irina-Kira [14]

Answer:

The rate determining step is step 1

Explanation:

6 0
3 years ago
Read 2 more answers
Which compound has the highest melting point? ch3(ch2)14cooh ch3(ch2)10ch=ch(ch2)2cooh ch3(ch2)2ch=ch(ch2)4ch=ch(ch2)4cooh ch3(c
Jlenok [28]
The compound with the highest melting point is CH3 [CH2]14COOH.
This compound has the highest melting point because it has the highest number of CH2 bonds. The melting point of a compound refers to a particular temperature at which that substance changes from a solid to a liquid.
7 0
4 years ago
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