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PilotLPTM [1.2K]
3 years ago
12

Which of the following will most likely happen if you apply unbalanced forces to an object? It will change position. It will bec

ome charged. It will change mass. It will change size.
Chemistry
2 answers:
Tasya [4]3 years ago
6 0

It will change position.

For example, you are pushing a water bottle. The push is a force that is imbalance because there is no other force pushing the water back. So if you push the water bottle, it will move. When it moves, it is also call, "Changing position" because its location changed.

Grace [21]3 years ago
4 0

Answer:

It will change position.

Explanation:

The forces can be either balanced or unbalanced. In balanced type of force the net force acting on the object is zero. The forces acting on both sides cancel out each other.

In unbalanced type of forces, the objects in a particular direction. The net force acting on the object is more than 1. As a result, the object will change its position.

Hence, the correct option is (a) "It will change position".

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Given 50g of sodium how many moles do you have? ​
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Amount of Na = 2.17moles

Explanation:

Mass of Na = 50g

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2NO + 3MnO2 + 4H â 2NO3- + 3Mn2 + 2H2O For the above redox reaction, assign oxidation numbers and use them to identify the eleme
mixer [17]

Answer:

Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).

Explanation:

Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^{2+} + 2H_2O

Next, we assign the oxidation numbers as follows:

2N^{2+}O^{2-} + 3Mn^{4+}O^{-2}_2 + 4H^+ \rightarrow 2(N^{5+}O^{2-}_3)^- + 3Mn^{2+} + 2H^+_2O^{2-}

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

Regards!

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3 years ago
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