Answer : The reaction 2 is spontaneous.
Explanation :
As we know that:
= +ve, reaction is non spontaneous
= -ve, reaction is spontaneous
= 0, reaction is in equilibrium
For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.
Reaction 1:
Glucose + Pi
glucose-6-phosphate + H₂O, ΔG = +13.8 kJ/mol
Reaction 2:
ATP + H₂O
ADP + Pi, ΔG = -30.5 kJ/mol
From this we conclude that the value of ΔG is negative. So, reaction 2 is a spontaneous reaction.
Answer:
[Acetic acid] = 0.07 M
[Acetate] = 0.13 M
Explanation:
pH of buffer = 5
pKa of acetic acid = 4.76
![pH=p_{Ka} + log\frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3Dp_%7BKa%7D%20%2B%20log%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now using Henderson-Hasselbalch equation
![5=4.76 + log\frac{[Acetate]}{[Acetic\;acid]}](https://tex.z-dn.net/?f=5%3D4.76%20%2B%20log%5Cfrac%7B%5BAcetate%5D%7D%7B%5BAcetic%5C%3Bacid%5D%7D)
![log\frac{[Acetate]}{[Acetic\;acid]} = 0.24](https://tex.z-dn.net/?f=log%5Cfrac%7B%5BAcetate%5D%7D%7B%5BAcetic%5C%3Bacid%5D%7D%20%3D%200.24)
....... (1)
It is given that,
[Acetate] + [Acetic acid] = 0.2 M ....... (2)
Now solving both the above equations
[Acetate] = 1.74[Acetic acid]
Substitute the concentration of acetate ion in equation (2)
1.74[Acetic acid] + [Acetic acid] = 0.2 M
[Acetic acid] = 0.2/2.74 = 0.07 M
[Acetate] = 0.2 - 0.07 = 0.13 M
To determine how stable the beads are as well ensue the securing of maximum enzymes as well as the retention of their activity.
<h3>What is concentration?</h3>
The concentration of a substance simply means the amount of the substance in solution. Thus we are looking at the amounts of sodium alginate and CaCl2 in the system.
The concentrations of the sodium alginate and CaCl2 is varied in order to determine how stable the beads are as well ensue the securing of maximum enzymes as well as the retention of their activity.
Learn more about enzymes:brainly.com/question/14953274
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Answer:
draw the carbon chain is containing 6 carbon then attach the aldehyde group with edge carbon in chain then put the put double bond at 3 no. carbon