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Artist 52 [7]
3 years ago
9

Answer 21 of 25 questions on his it history test correctly what does the decimal represents the fraction of the

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

0.16

Step-by-step explanation:

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{(6,4),(7,−3),(−4,3),(8,−3)}, which point if added would not create a function?
Lera25 [3.4K]

Answer:

Step-by-step explanation:

What points were you given to choose from?

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Why maths is an abstract subject​
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Abstraction in mathematics is the process of extracting the underlying structures, patterns or properties of a mathematical concept, removing any dependence on real world objects with which it might originally have been connected, and generalizing it so that it has wider applications or matching among other abstract
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4 years ago
-4 is less than or equal to 2t + 5 which is less than 11
dlinn [17]
Not sure what you’re trying to find but here’s the simplified version:

-4<=2t+5<11
-9<=2t<6
-9/2<=t<3
7 0
4 years ago
Read 2 more answers
Which answer choice shows 4 + 0.3 + 0.09 written in standard form?A.43.9B.4.39C.0.439D.0.0439
Oliga [24]

Place values:

As each is in a different place value, when we add them neither will affect the other, meaning:

4+0.3+0.09=4.39

Answer: B 4.39

5 0
1 year ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
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