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sattari [20]
3 years ago
14

7 less than -2 times a number x is greater than or equal to 41.

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0
1. It is 7 - -2 x ( Variable ) > 41
                                              -
( When a line is under the > sign, that means that it is either greater or the same )

2. I'm confused on it tbh.

3. 7 - -2 x ( any number higher than 4 )  > 41 
                                                                -
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What is the equation of the following line written in slope-intercept form?
nasty-shy [4]
SOLUTION:

To begin with, let's establish that the formula of this line is in slope-intercept form as follows:

y = mx

The formula for this line isn't:

y = mx + b

This is as this line doesn't have a y-intercept ( b ) as it passes through the origin instead. This means that ( b ) would be rendered useless in this formula as it would just bring us back to the y = mx formula as displayed below:

y = mx + b
y = mx + 0
y = mx

Moving on, for ( m ), we need to find the gradient of the line as displayed below:

m = gradient
m = rise / run
m = 10 / 2
m = 5

Now, we must simply substitue ( m ) into the formula in order to obtain the equation for this line as displayed below:

y = mx
y = 5x

Therefore, the answer is:

A. y = 5x
6 0
3 years ago
PLEASE HELPPPPPPP
uysha [10]

Answer:

the answer would be 1,-8

6 0
2 years ago
Audrey Lorenz assembles gift baskets for a florist. The owner pays her $0.45 per small basket and $0.75 per large basket on Tues
Gemiola [76]

Answer:

Step-by-step explanation:

(.45)(288)= $129.60

(.75)(72)= $54

$129.60 + 54 = $184.60 is Audrey's pay

3 0
3 years ago
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7 0
3 years ago
Which of the following shows the true solution to the logarithmic equation 3 log Subscript 2 Baseline (2 x) = 3
VARVARA [1.3K]

Answer:

x = 1

Step-by-step explanation:

We have to solve the given logarithmic equation of variable x.

The equation is 3\log _{2} (2x) = 3

⇒ \log_{2} (2x)^{3} = 3  

{Since, we know the logarithmic property, a \log b = \log b^{a}}

⇒ \log_{2} (2x)^{3} = 3\log_{2}2 = \log_{2} 2^{3}

{Since we know that \log_{a} a = 1}

Now cancelling log from both sides we get,  

(2x)^{3} = 2^{3}

⇒ x^{3} = 1

⇒ x = 1 (Answer)

7 0
3 years ago
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