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aliina [53]
3 years ago
6

Which two processes increase the motion of the molecules?

Physics
1 answer:
anzhelika [568]3 years ago
5 0
The answer is 2 because a and b are slowing it down by condensing it and then freezing it so its not one, b and c are opposites because b slows it down whereas c speeds it up so its not 3, and number 4 is the same explanation for number 3
hope you pass :)
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A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used
Blizzard [7]

Answer:

a,b)   #_ {electron} = 1.64 10¹⁹ electrons, c)  R = 19.54  Ω, d)   V = 10.3 V

Explanation:

a and b) The current is defined as the number of electrons that pass per unit of time

let's look for the load

            Q = I t

            Q = 0.526  5

            Q = 2.63 C

Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?

           #_ {electron} = 2.63 C (1 electron / 1.6 10⁻¹⁹)

           #_ {electron} = 1.64 10¹⁹ electrons

         

c) the resistance of a wire is given by

          R = ρ l / A

           

where the resistivity of tungsten is 5.6 10⁻⁸ Ω

the area of ​​the wire is

           A = π r2 = π d²/4

         

we substitute

            R = \rho \ l \ \frac{4}{\pi  d^2}

let's calculate

           R = 5.6 10⁻⁸  0.580 \frac{4}{ \pi  (0.046 \ 10^{-3})^2 }

           R = 19.54  Ω

d) let's use ohm's law

           V = i R

            V = 0.526 19.54

            V = 10.3 V

7 0
2 years ago
a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what w
nataly862011 [7]

Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load  distance=10 cm

We have to find the effort distance.

We know that

load\times load\;distance=Effort\times effort\;distance

Using the formula

800\times 10=200\times effort\;distance

Effort distance=\frac{800\times 10}{200}

Effort distance=\frac{8000}{200}

Effort distance=40 cm

Hence,  the effort distance will be 40 cm.

7 0
3 years ago
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