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3 years ago

Which two processes increase the motion of the molecules?

Physics

1 answer:

anzhelika [568]3 years ago

5 0

The answer is 2 because a and b are slowing it down by condensing it and then freezing it so its not one, b and c are opposites because b slows it down whereas c speeds it up so its not 3, and number 4 is the same explanation for number 3
hope you pass :)

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calculate the energy spent on spraying a drop of mercury of 1 cm radius into 10^6 droplets all of same radius. surface tension o

WARRIOR [948]

Answer:

ANS : .Energy spent on spraying = $4.3542*10^{-4}J$

Explanation:

Given:

Radius of mercury = 1cm initially ;
split into $10^{6}$ drops ;

Thus, volume is conserved.

i.e ,

$\frac{4}{3} \pi R_{o}^{3} = 10^{6}*\frac{4}{3} \pi R_{n}^{3}\\R_{n}=\frac{R_{o}}{10^{2}} = \frac{1cm}{100} = 0.01 cm$

Energy of a droplet = $T$ Δ $A$

Where ,

T is the surface tension
ΔA is the change in area

Initial energy $E_{i} = T*A_{i}\\= 0.0035 * 4 *\pi *0.01^{2}\\=4.398*10^{-6}J$

Final energy $E_{f}=10^{6}*T*A_{f}\\=10^{6}*0.0035*4*\pi *(0.0001)^2\\=4.39823*10^{-4}$

∴ .Energy spent on spraying = $=E_{f}-E{i}\\=(439.823-4.39823)*10^{-6}\\=4.3542*10^{-4}J$

ANS : .Energy spent on spraying = $4.3542*10^{-4}J$

6 0

2 years ago

A european car manufacturer reports that the fuel efficiency of the new microcar is 28.5 km/l highway and 22.0 km/l city. what a

Studentka2010 [4]

We know that:

1 mile = 1.61 km

1 gal = 3.8 L

Therefore converting the fuel efficiency rates:

highway = (28.5 km/L) * (1 mile / 1.61 km) * (3.8 L / 1 gal) = 67.27 mile / gal

city = (22.0 km/L) * (1 mile / 1.61 km) * (3.8 L / 1 gal) = 51.93 mile / gal

4 0

2 years ago

A student made the following observations about a squirrel’s movements:

dalvyx [7]

The correct option is D.

Qualitative observations are observations that are made using our senses of sight, hearing, smell, taste and feel. These observations do not involve numbers or measurements of any kind.

The student's observations regarding the squirrel as is mentioned in options A, B and C involve measurements. Therefore these are not qualitative observations.

Option D, however, is made on the basis of sight, where the student observes the squirrel moving in a zigzag manner.

Therefore, of all the three observations, the student's observation that the squirrel ran in a zigzag pattern is the qualitative observation.

4 0

2 years ago

A gas expands against a constant external pressure of 2.00 atm until its volume has increased from 6.00 to 10.00 L. During this

mars1129 [50]

Answer:

ΔU = - 310.6 J (negative sign indicates decrease in internal energy)

W = 810.6 J

Explanation:

Using first law of thermodynamics:

Q = ΔU + W

where,

Q = Heat Absorbed = 500 J

ΔU = Change in Internal Energy of Gas = ?

W = Work Done = PΔV =

P = Pressure = 2 atm = 202650 Pa

ΔV = Change in Volume = 10 L - 6 L = 4 L = 0.004 m³

Therefore,

Q = ΔU + PΔV

500 J = ΔU + (202650 Pa)(0.004 m³)

ΔU = 500 J - 810.6 J

ΔU = - 310.6 J (negative sign indicates decrease in internal energy)

The work done can be simply calculated as:

W = PΔV

W = (202650 Pa)(0.004 m³)

W = 810.6 J

7 0

2 years ago

The impact of the type of material of which the slope is made on acceleration

Pachacha [2.7K]

The impact of the material type with which the slope is made affects the acceleration. Acceleration will be higher and smoother if the material of the slope surface is smoother as opposed to a texture which is not smooth. Smoother surface allows more acceleration because it will have less friction and resistance. Otherwise the friction will slow the object down for example a grassy ground will have more friction than a well maintained marble floor.

6 0

2 years ago