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Vinvika [58]
3 years ago
6

A basketball player is running at 4.80 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains

his horizontal velocity. (a) What vertical velocity (in m/s) does he need to rise 0.650 meters above the floor? _______m/s (b) How far (in m) from the basket (measured in the horizontal direction) must he start his jump to reach his maximum height at the same time as he reaches the basket?_______m
Physics
1 answer:
Levart [38]3 years ago
7 0

Answer:

a) 3.56m/s

b) 1.73m

Explanation:

We have to treat this as a parabolic motion problem:

we will use the next formulas:

V=Vo+a*t\\Vy^2=Vyo^2+2*a*Y\\X=Vox*t

we first have to calculate the initial velocity of the basketball player:

Vy^2=Vyo^2+2*a*Y\\0^2=Vyo^2+2*(-9.8)*(0.650)\\Vyo=\sqrt{2*9.8*0.650} \\Vyo=3.56 m/s

the final velocity is zero when he reaches the maximun height.

To answer the second part we need to obtain the time to reach the maximun height, so:

V=Vo+a*t\\\\0=3.56+(-9.8)*t\\t=0.36 seconds

Now having that time, let's find the distance on the X axis, the X axis behaves as constant velocity movement, so:

X=Vox*t\\X=4.80*0.36\\X=1.73m

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Answer:

Density (φ) = 0,8827 Kg/L

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Explanation:

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Answer:

             

Explanation:

is  A projectile is any object on which the only force acting is gravity and air resistance (drag).

Examples of projectiles are:

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golf balls hit by a club

objects dropped from aircraft, such as people (skydivers), bombs, crates of food being dropped to refugees

objects launched by cannons, such as cannonballs, shells, and circus performers

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Here is an online projectile motion applets to play with, just for fun.

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The only common variable between these two equations is t, the time. Because in projectile problems there is usually no acceleration (i.e. we ignore air resistance) in the horizontal direction, we can write

           

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