0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.
Explanation:
Data given:
volume of the nitrogen gas = 2 litres
Standard temperature = 273 K
Standard pressure = 1 atm
number of moles =?
R (gas constant) = 0.08201 L atm/mole K
Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law
PV = nRT
rearranging the equation to calculate number of moles:
PV = nRT
n = 
putting the values in the equation:
n = 
n = 0.091 moles
0.091 moles of nitrogen gas is contained in a container at STP.
Answer: 1.2 x 10^-17 microounces
Explanation:
Ounce = 28.5G microounce = 28.5*10^-6g
3.4*10^-25 kg = 3.4*10^-22 g = (3.4/2.85)*10^(-22+5) = 1.2*10-17
Answer: -
12.41 g
Explanation: -
Mass of CO₂ = 42 g
Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol
Number of moles of CO₂ = 
= 0.9545 mol
The balanced chemical equation for this process is
2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O
From the balanced chemical equation we see
12 mol of CO₂ is produced from 2 mol of C₆H₆
0.9545 mol of CO₂ is produced from 
= 0.159 mol of C₆H₆
Molar mass of C₆H₆ = 12 x 6 + 1 x 6 =78 g /mol
Mass of C₆H₆ =Molar mass x Number of moles
= 78 g / mol x 0.159 mol
= 12.41 g
KCI (s) contains particles in a rigid, fied, geometric pattern.
Three quantities/variables are needed in order to calculate the amount of heat given off or absorbed during a chemical reaction are the substance, the process and the amount of substance.
When a substance in the same state absorbs heat, its temperature increases.
The amount of heat absorbed is proportional to the amount of the substance and the increase in temperature.
The amount of heat needed to raise the temperature of one gram of substance by 1°C is called the specific heat of that substance.
The specific heat of water is 4.18 J/g°C.
The amount of heat, q, absorbed by a given mass (m) of substance with specific heat, s, when its temperature increases by ΔT is given by the following formula: q = m × s × ΔT.
More about amount of heat: brainly.com/question/25603269
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