Answer:
0.29 moles of PbCl₂
Explanation:
Given data:
Mass of lithium chloride = 24.3 g
Moles of PbCl₂ = ?
Solution:
Chemical equation;
PbSO₄ + 2LiCl → PbCl₂ + Li₂SO₄
Number of moles of LiCl:
Number of moles = mass/ molar mass
Number of moles = 24.3 g/ 42.394 g/mol
Number of moles = 0.57 mol
Now we will compare the moles of PbCl₂ with LiCl .
LiCl : PbCl₂
2 : 1
0.57 : 1/2×0.57 = 0.29 mol
Answer:
You should not use an open flame to heat the solvent and the solvent should be heat in a stoppered flask to vapour away from the open flame
Explanation:
Answer:
2Fe(s) + O₂(g) + 2H₂O(l) → 2Fe(OH)₂(s)
Explanation:
