12 cm x 2 cm x 3 cm = 72 cm3
Answer:
F_total = 29.4 N, directed to the right of particle 2
Explanation:
We must solve this problem in parts, first we calculate each force and then we apply Newton's law to add the forces.
Let's use Coulomb's law to calculate each force
F =
particles 1 and 2
q₁ = 8.0 10⁻⁶ C, q₂ = 3.5 10⁻⁶ C x₁₂ = 0.10 m
F₁₂ = 9 10⁹ 8.0 3.5 10⁻¹² / 0.1²
F₁₂ = 2.59 10¹ N
Since the two charges are of the same sign, this force is repulsive and is directed towards the positive side of the x axis.
particles 2 and 3
q₂ = 3.6 10⁻⁶ C, q₃ = 2.5 10⁻⁶ C, x₂₃ = 0.15 m
we calculate
F₂₃ = 9 10⁹ 3.5 2.5 10⁻¹²/ 0.15²
F₂₃ = 3.5 N
as the charge is of different sign, the force is attractive, therefore it is directed to the right of the load 2
Now we add the forces as vectors
F_total = ∑ F = F₁₂ + F₂₃
F_total = 25.2 +3.5
F_total = 29.4 N
directed to the right of particle 2
<h2>
The current rotational period of that star is 10.01 hours.</h2>
Explanation:
Given that,
Initial angular velocity of the star,
It decelerates, final angular speed,
Deceleration,
It is not required to use the rotational kinematics formula. The angular velocity in terms of time period is given by :
T is current rotational period of that star
T = 36036.03 second
or
1 hour = 3600 seconds
So, T = 10.01 hours
So, the current rotational period of that star is 10.01 hours. Hence, this is the required solution. Hence, this is the required solution.
Answer:
Power required will be 7.2 watt
Explanation:
We have given battery of Barble jeep is 6 volt
So potential difference V = 6 volt
Resistance of electric motor R = 5 ohm '
We have to find the power motor using to drive the jeep
Power is given by , here V is voltage and R is resistance
So