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Ksenya-84 [330]

3 years ago

11

Would you expect the tensile strength of polychlorotrifluoroethylene to be greater, the same as, or less than that of a polytetr

afluoroethylene specimen having the same molecular weight and degree of crystallinity?

1 answer:

lbvjy [14]3 years ago

3 0

Answer:

idk

Explanation:

idk

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A box of bananas weighing 40.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surfa

Burka [1]

Answer:

(a) = 0 N

(b) = 2.4 N

Explanation:

given

box of banana weight = 40.0 N

coefficient of static friction μ = 0.40

coefficient of kinetic friction = 0.20

a). when no horizontal force is applied .

according to Newton 's third law of motion If there is no force applied to the box,so the frictional force exerted is 0 N

b) magnitude of friction force

box and the box is initially at rest

friction force =.Static friction coefficient × weight of the box

friction force = 0.40 × 6

friction force = 2.4 N

8 0

2 years ago

A cup of water is warmed from 21 °C to 85 °C. What is the difference between these two temperatures, in kelvins?

Ilya [14]

Answer:

337k

Explanation:

First, let us find the difference between the given two temperatures.

Difference = 85°C - 21°C

= 64°C

<u>And now we have to write the temperature in kelvins.</u>

To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.

<u>Let us find it now.</u>

64°C + 273 = 337k

Therefore,

64°C ⇒ <u>337k</u>

8 0

1 year ago

A 20 g bullet is shot from a 10 kg gun with a velocity of 400 m/s. What

Nady [450]

Answer: -.80m/s

Explanation:

3 0

3 years ago

A cruise ship sails due south at 2.00 m/s while a coast guard patrol boat heads 19.0° north of east at 5.60 m/s. What are the x-

Lilit [14]

Answer:

The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

Explanation:

Given that,

Velocity of ship = 2.00 m/s due south

Velocity of boat = 5.60 m/s due north

Angle = 19.0°

We need to calculate the component

The velocity of the ship in term x and y coordinate

$v_{s_{x}}=0$

$v_{s_{y}}=2.0\ m/s$

The velocity of the boat in term x and y coordinate

For x component,

$v_{b_{x}}=v_{b}\cos\theta$

Put the value into the formula

$v_{b_{x}}=5.60\cos19$

$v_{b_{x}}=5.29\ m/s$

For y component,

$v_{b_{y}}=v_{b}\sin\theta$

Put the value into the formula

$v_{b_{y}}=5.60\sin19$

$v_{b_{y}}=1.82\ m/s$

We need to calculate the x-component and y-component of the velocity of the cruise ship relative to the patrol boat

For x component,

$v_{sb_{x}}=v_{s_{x}}-v_{b_{x}}$

Put the value into the formula

$v_{sb_{x}=0-5.29$

$v_{sb}_{x}=-5.29\ m/s$

For y component,

$v_{sb_{y}}=v_{s_{y}}-v_{b_{y}}$

Put the value into the formula

$v_{sb_{x}=2.-1.82$

$v_{sb}_{x}=0.18\ m/s$

Hence, The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

7 0

3 years ago

Alkali metals _____.

Lyrx [107]

I think the answer is C

7 0

2 years ago