Answer:
(a) 
(b) 
(c) 
Explanation:
First change the units of the velocity, using these equivalents 
and 
The angular acceleration 
the time rate of change of the angular speed 
according to:
Where 
is the original velocity, in the case the velocity before starting the deceleration, and 
is the final velocity, equal to zero because it has stopped.
b) To find the distance traveled in radians use the formula:
To change this result to inches, solve the angular displacement 
for the distance traveled 
(
is the radius).
c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:
The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle 
is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which is also the net displacement):
Answer:
95 %
99.7 %
Explanation:
= 166 cm = Mean
= 5 cm = Standard deviation
a) 156 cm and 176 cm
From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.
b) 151 cm and 181 cm
The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.
Answer:
Final mass=0.89kg
Final pressure=5.6bar
Explanation:
To find mass,m=v/v1
But v1=vf + x(vg-vf)
Vf= 0.001093m^3/kg
Vg= 0.3748m^3/kg
V1= 0.001093+0.5(0.3748-0.001093)
V1= 0.225m^3/kg
M= 0.20/0.225 =0.89kg
Final pressure will be:
V/V1= P/P1
Cross multiply
VP1=V1P
P1= 0.225×5/0.2
P1=:5.6 bar
Answer:
Explanation:
Given that there are two force of 1 pound each at right angles to each other.
The from the vector law of addition:
where:
resultant force
be the two of the forces to be added.
