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Orlov [11]
3 years ago
8

Identify how scientists use radioactive isotopes by selecting the best answers from the drop-down menus. Archaeologists use radi

oactive isotopes to ___________ Scientists use radioactive isotopes in agriculture to_____________ Geologists use radioactive isotopes to ______________
Physics
2 answers:
salantis [7]3 years ago
6 0

Answer:

Archaeologist use radioactive isotopes to determine the ages of various objects, rocks and materials. This is called radioactive dating. Radioactive isotope Carbon-14 is widely used for this dating process.

Scientists use radioactive isotopes in agriculture to monitor or study the uptake and use of essential nutrients by plants from the soil. This helps to determine viability, productivity and nutritious ability of the plants on a piece of land.

Geologists use radioactive isotopes to trace leaks in underground water storage, pipes. Radioactive isotopes are effective tracers because their radioactivity can be easily detected.

SpyIntel [72]3 years ago
5 0

Answer:

Explanation:

Archaeologists use radioactive isotopes for Radiometric dating which is typically a method of dating based on the rate of decay of radioactive isotopes present in all organic materials.

The radiometric dating technique tyat is Carbon-14 or radiocarbon is used widely in archaeology.

Scientists use radioactive isotopes in agriculture as research tools in the development of new strains of agricultural crops that are drought and disease resistant, of higher quality, have shorter growing time and produce a higher yield of produce.

Radioactive elements can be used to understand numerical age of geological materials like rock ages, composition, origin etc. on time scales as long as (and even longer than) the age of the Earth. The use of Radiometric dating is employed.

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A particle moves in a velocity field V(x, y) = x2, x + y2 . If it is at position (x, y) = (7, 2) at time t = 3, estimate its loc
MArishka [77]

Answer:

New location at time 3.01 is given by: (7.49, 2.11)

Explanation:

Let's start by understanding what is the particle's velocity (in component form) in that velocity field at time 3:

V_x=x^2=7^2=49\\V_y=x+y^2=7+2^2=11

With such velocities in the x direction and in the y-direction respectively, we can find the displacement in x and y at a time 0.01 units later by using the formula:

distance=v\,*\, t

distance_x=49\,(0.01)=0.49\\distance_y=11\,(0.01)=0.11

Therefore, adding these displacements in component form to the original particle's position, we get:

New position: (7 + 0.49, 2 + 0.11) = (7.49, 2.11)

6 0
3 years ago
Use the work—energy theorem to solve each of these problems. You can use Newton's laws to check your answers. Neglect air resist
andreyandreev [35.5K]

Answer:

a) It is moving at 43.15\frac{m}{s^{2}} when reaches the ground.

b) It is moving at 101.44\frac{m}{s^{2}} when reaches the ground.

Explanation:

Work energy theorem states that the total work on a body is equal its change in kinetic energy, this is:

W=K_f-K_i (1)

with W the total work, Ki the initial kinetic energy and Kf the final kinetic energy. Kinetic energy is defined as:

K=\frac{mv^2}{2} (2)

with m the mass and v the velocity.

Using (2) on (1):

W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (3)

In both cases the total work while the objects are in the air is the work gravity field does on them. Work is force times the displacement, so in our case is weight (w=mg) of the object times displacement (d):

W=Fd=wd=mgd (4)

Using (4) on (3):

mgd=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (5)

That's the equation we're going to use on a) and b).

a) Because the branch started form rest initial velocity (vi) is equal zero, using this and solving (5) for final velocity:

v_f=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*95}

v_f=43.15\frac{m}{s^{2}}

b) In this case the final velocity of the boulder is instantly zero when it reaches its maximum height, another important thing to note is that in this case work is negative because weight is opposing boulder movement, so we should use -mgd:

-mgd=-\frac{mv_i^2}{2}

Solving for initial velocity (when the boulder left the volcano):

v_i=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*525}

v_i=101.44 \frac{m}{s^{2}}

3 0
3 years ago
A plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy. Which organelle is m
Nadya [2.5K]

The chloroplast of the cell is most likely damaged if the plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy.

The chloroplast is the structure inside the leaf cell that is known for capturing light energy from the sun.

This light energy is then used to make food that has chemical energy. If a plant cell has a damaged chloroplast or the chloroplast is removed, then it will no longer be able to trap the light energy. As a result, the process of photosynthesis will not occur in the plant cell. The plant cell will not be able to make the chemical energy required for functioning.

To learn more about chloroplast, click here:

brainly.com/question/1741612

#SPJ4

8 0
1 year ago
Business are necessary in order to preform which of the following functions
NeTakaya

Answer:

Hire, organize, and supply workers.

Explanation:

7 0
3 years ago
Plz answer this! I am stumped
Gwar [14]
MgCl2
Mg = magnesium
Cl = chlorine

Magnesium + chlorine = magnesium chloride.

This is because compounds are always written with the METAL FIRST and the NON METAL SECOND. the non metal ends in - ide when it reacts with a metal.

So ur answer would be magnesium chloride. :)
6 0
4 years ago
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