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Orlov [11]
3 years ago
8

Identify how scientists use radioactive isotopes by selecting the best answers from the drop-down menus. Archaeologists use radi

oactive isotopes to ___________ Scientists use radioactive isotopes in agriculture to_____________ Geologists use radioactive isotopes to ______________
Physics
2 answers:
salantis [7]3 years ago
6 0

Answer:

Archaeologist use radioactive isotopes to determine the ages of various objects, rocks and materials. This is called radioactive dating. Radioactive isotope Carbon-14 is widely used for this dating process.

Scientists use radioactive isotopes in agriculture to monitor or study the uptake and use of essential nutrients by plants from the soil. This helps to determine viability, productivity and nutritious ability of the plants on a piece of land.

Geologists use radioactive isotopes to trace leaks in underground water storage, pipes. Radioactive isotopes are effective tracers because their radioactivity can be easily detected.

SpyIntel [72]3 years ago
5 0

Answer:

Explanation:

Archaeologists use radioactive isotopes for Radiometric dating which is typically a method of dating based on the rate of decay of radioactive isotopes present in all organic materials.

The radiometric dating technique tyat is Carbon-14 or radiocarbon is used widely in archaeology.

Scientists use radioactive isotopes in agriculture as research tools in the development of new strains of agricultural crops that are drought and disease resistant, of higher quality, have shorter growing time and produce a higher yield of produce.

Radioactive elements can be used to understand numerical age of geological materials like rock ages, composition, origin etc. on time scales as long as (and even longer than) the age of the Earth. The use of Radiometric dating is employed.

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3- A ball of mass 0,50 kg falls and hits the floor at 10m/s,
Klio2033 [76]

Answer:

3- A ball of mass 0,50 kg falls and hits the floor at 10m/s,

It rebounds at speed 8.0 m/s, as shown.

before collision

after collision

10 m/s

8 m/s

The collision between the ball and the floor lasts for 0.50 s.

What is the average force acting on the ball during the collision?

4 0
3 years ago
witch of the following is the least reliable source of background information for a scientific project.
Tems11 [23]

Primary sources are most often produced around the time of the events you are studying.


hopwe this helps

3 0
4 years ago
Read 2 more answers
In the double-slit experiment with electrons, the electrons arrive at the screen in a
Y_Kistochka [10]

Answer:

B. Wave-like way with a pattern that is wave-like

Explanation:

The double slit experiment when performed with electromagnetic waves, gives a pattern of light lines and dark areas, equally spaced.

In the case of electrons we must use Broglie's duality principle that states that all things have the characteristics of particles and waves together. The characteristic observed in a given experiment depends on the type of experiment, using the relationship

          p = h /λ

Where p is the amount of motion of the particle and λ the wavelength associated with this particle

In consequence of the previous one to the screen it should arrive as a wave with a wave type pattern

Let's review the answer.

A) False. The pattern is wave type

B) True. The whole process is with undulating characteristics

C) False. A wave arrives

D) False. A wave arrives

4 0
3 years ago
The first law of thermodynamics states that E=Q-W. How is this also a statement of the principle of conservation of energy?
g100num [7]
This law demonstrates that the energy within a close system may be converted from one form to another, but it cannot be created nor destroyed.
4 0
3 years ago
Calculate the first and second order angles for light of wavelength 400. nm and 700. nm of the grating contains 1.00 x 104 lines
Verdich [7]

Answer:

23.58^{\circ} and 53.13^{\circ}

44.43^{\circ}, second order does not exist

Explanation:

n = Number of lines grating = 1\times10^4\ \text{Lines/cm}

\lambda = Wavelength

m = Order

Distance between slits is given by

d=\dfrac{1}{n}\\\Rightarrow d=\dfrac{1}{1\times 10^4}\\\Rightarrow d=10^{-6}\ \text{m}

\lambda=400\ \text{nm}

m = 1

We have the relation

d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}\\\Rightarrow \theta=\sin^{-1}\dfrac{1\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=23.58^{\circ}

m = 2

\theta=\sin^{-1}\dfrac{2\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=53.13^{\circ}

The first and second order angles for light of wavelength 400 nm are 23.58^{\circ} and 53.13^{\circ}.

\lambda=700\ \text{nm}

m = 1

\theta=\sin^{-1}\dfrac{1\times 700\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=44.43^{\circ}

m = 2

\theta=\sin^{-1}\dfrac{2\times 700\times 10^{-9}}{10^{-6}}

Here \dfrac{2\times 700\times 10^{-9}}{10^{-6}}=1.4>1 so there is no second order angle for this case.

The first order angle for light of wavelength 700 nm are 44.43^{\circ}.

Second order angle does not exist.

5 0
3 years ago
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