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NARA [144]
2 years ago
9

A toy car pushed across the floor is observed to slow down and stop based on Newton’s first law of motion what is the best concl

usion
A : an object in motion eventually stops
B. The car must have been going slightly uphill
C. The car did not have enough mass to keep going
D. There must have been an unbalanced force acting on the toy car
Physics
1 answer:
Maksim231197 [3]2 years ago
3 0

An object in motion eventually stops because of friction.

<h3>What is Newton’s first law of motion?</h3>

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or continue its moving in a straight line at constant speed unless force is applied on it.

So we can conclude that An object in motion eventually stops is the correct answer.

Learn more about law here: brainly.com/question/820417

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By holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. Therefore, the direction of the force on the charge you are holding will be to the southwest.

Let I hold the charge , q at the centre of given co-ordinate system and two positive charge of equal magnitude Q are placed 1 m to my North and 1 m to my South .

now, both the charge are same nature e.g., positive . Let my charge is also positive (well, you can assume negative too , I am considering positive because it makes me easy to solve) then, both charge repel to my charge.

charge Q placed on east is repelling my charge q toward west . similarly charge Q placed on North is repelling my charge q toward south.

Now , use vector for solve it.

vector F_{net} = vector Fe + vector Fn,

⇒ |F_{net}| = \sqrt{}  F^{2} _{e } + F^{2}_n

⇒ Fe = Fs = KqQ/(1m)² = KqQ

⇒ F_{net} = √{Fe² + Fs²} = √{(kqQ)²+(KqQ)²}

⇒ F_{net}= √2KqQ

Hence, net force act on q {my charge } is √2KqQ and the direction of force is S - W (southwest )direction.

To learn more about positive charges here

brainly.com/question/2903220

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