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2 years ago

When do we use v=2s/t and what does that equation mean?

Physics

1 answer:

djyliett [7]2 years ago

5 0

Answer:

This can be used to find out the speed of the returned journey. The equation means speed = returned distance ÷ time.

Explanation:

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The graph represents the change in that occurs when food is cooked over a charcoal grill. Which statement correctly explains the

MArishka [77]

Option C is the answer

<h3 /><h3>Small Explanation:-</h3>

The reactants are charcoal that is unlit + oxygen and the products are the burnt charcoal + energy.

(Explanation with formula and reason attached. Check it.)

$> Benjemin360$

6 0

2 years ago

A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum outp

Maslowich

Answer:

695800 N/m^2 or Pa

Explanation:

Height of the water from the ground H = 71 m

Acceleration due to gravity g =9.8 m/s^2

density of water ρ= 1000 kg/m^3

The minimum output gauge pressure to make water reach height H

P= ρgH

= 1000×9.8×71= 695800 N/m^2 or Pa

5 0

2 years ago

Learning Task 2: Write the words that can be associated with the ''Music During Classical Era''. You may ask help from the membe

Natasha_Volkova [10]

Answer:

classical

concert

exposition

orchesta

devolopment

recapitulation

sympathy

sonata

sinfonia

soloist

Explanation:

5 0

2 years ago

An inductor has inductance of 0.260 H and carries a current that is decreasing at a uniform rate of 18.0 mA/s.

nignag [31]

Answer:

The self-induced emf in this inductor is 4.68 mV.

Explanation:

The emf in the inductor is given by:

$\epsilon = -L\frac{dI}{dt}$

Where:

dI/dt: is the decreasing current's rate change = -18.0 mA/s (the minus sign is because the current is decreasing)

L: is the inductance = 0.260 H

So, the emf is:

$\epsilon = -L\frac{dI}{dt} = -0.260 H*(-18.0 \cdot 10^{-3} A/s) = 4.68 \cdot 10^{-3} V$

Therefore, the self-induced emf in this inductor is 4.68 mV.

I hope it helps you!

6 0

2 years ago

A 150-W lamp is placed into a 120-V ac outlet. What is the peak current?

devlian [24]

Answer:

Explanation:

Formula

W = I * E

Givens

W = 150

E = 120

I = ?

Solution

150 = I * 120 Divide by 120

150/120 = I

5/4 = I

I = 1.25

Note: This is an edited note. You have to assume that 120 is the RMS voltage in order to go any further. That means that the peak voltage is √2 times the size of 120. The current has the same note applied to it. If the voltage is its rms value, then the current must (assuming the properties of the bulb do not change)

On the other hand, if the voltage is the peak value at 120 then 1.25 will be correct.

However I would go with the other answerer's post and multiply both values by √2

3 0

3 years ago

Read 2 more answers